Hi Phillip,
Try this:
as.Date(c("20180329","20180330","20180331"),"%Y%m%d")
[1] "2018-03-29" "2018-03-30" "2018-03-31"
Note that the format argument has to match the date format exactly.
Jim
On Wed, Sep 25, 2019 at 9:54 AM Phillip Heinrich <herd_...@cox.net> wrote:
>
> The date is imbedded in the GameID character field so I created a date vector
> with the following code:
>
> ari18.test3$date <- substring(ari18.test3$GameID,4,11) And then created a
> new dataframe with just the Game ID and date vectors. The date field is a
> character as shown by the str() command. str(test)
> 'data.frame': 3 obs. of 2 variables:
> $ GameID: Factor w/ 3 levels "ARI201803290",..: 1 2 3
> $ date : chr "20180329" "20180330" "20180331" GameID date
> 1 ARI201803290 20180329
> 81 ARI201803300 20180330
> 165 ARI201803310 20180331
> > My notes from about a week ago say that the following code will turn “date”
> > into a date field: test$date <- as.Date(test$date,format="%Y %M %D") date
> > becomes a date field but the data disappears into NA str(test)
> 'data.frame': 3 obs. of 2 variables:
> $ GameID: Factor w/ 3 levels "ARI201803290",..: 1 2 3
> $ date : Date, format: NA NA NA What am I missing here?
> [[alternative HTML version deleted]]
>
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