What happens if you use key=year? Also, tables get mangled when you post in HTML to plain-text list.
On Mon, Jul 15, 2019 at 6:47 PM <reichm...@sbcglobal.net> wrote: > > r-help > > > > Needing to transform some data for a time series (1930 - 2018). > > > > > tempDat > # A tibble: 89 x 13 > Year Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov > Dec > <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> > <dbl> > 1 1930 52 60.3 60.6 72.2 71.7 86.8 91.3 89.7 82.3 70.4 60.2 > 52.2 > 2 1931 52.9 57.8 62.7 72.4 80.5 87 95.1 89.3 85.9 72.8 57.2 > 49.7 > 3 1932 47 56.8 61.9 69.3 77.2 84.7 91.9 92.1 87 71.5 62.9 > 49.3 > > If I use the gather function: > > > > tempDat.long <- gather(data=tempDat, key=month, value=temp, "Jan", "Feb", > "Mar", > > > "Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec") > > > > > tempDat.long > # A tibble: 1,068 x 3 > Year month temp > <dbl> <chr> <dbl> > 1 1930 Jan 52 > 2 1931 Jan 52.9 > 3 1932 Jan 47 > 4 1933 Jan 48.8 > 5 1934 Jan 54.5 > > > > But I need it to be > > > > Year month temp > <dbl> <chr> <dbl> > 1 1930 Jan xx.x > 2 1930 Feb xx.x > 3 1930 Mar xx.x > 4 1930 Apr xx.x > 5 1930 May xx.x > > > > So would I need to use the lubridate package to rearrange my data or is > there a more straight forward method? > > > > > > Jeff Reichman > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.