Thanks! That works!! Duncan Murdoch <murdoch.dun...@gmail.com> 於 2019年2月27日 週三 下午12:06寫道:
> On 26/02/2019 10:34 p.m., John wrote: > > If I use the na.locf function to replace each NA with the most recent > > non-NA prior to it, then > > > >> na.locf(c(NA,NA,1,4,NA,2)) > > [1] 1 1 1 4 4 2 > > > > I want to keep leading NA's, and this is what I want > > NA NA 1 4 4 2 > > > > How can I do it? > > > > The following do not work: > > > >> na.locf(c(NA,NA,1,4,NA,2), na.rm=FALSE) > > Error in na.locf(c(NA, NA, 1, 4, NA, 2), na.rm = FALSE) : > > unused argument (na.rm = FALSE) > >> na.locf(c(NA,NA,1,4,NA,2), na.rm=TRUE) > > Error in na.locf(c(NA, NA, 1, 4, NA, 2), na.rm = TRUE) : > > unused argument (na.rm = TRUE) > > > > > > Thank you very much! > > > There are at least two packages (zoo and imputeTS) which have na.locf > functions. The one in zoo does what you want: > > > zoo::na.locf(c(NA,NA,1,4,NA,2), na.rm=FALSE) > [1] NA NA 1 4 4 2 > > Duncan Murdoch > > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.