On 08/01/2019 4:28 a.m., Nick Wray via R-help wrote:
y<-c(1,2,3)
z<-which(y>3)
At this point z is a vector with no entries in it.
z
y<-y[-z]
-z is the same vector. So y[z] and y[-z] are the same.
y
In the work I'm doing I often have this situation and have to make sure that I
condition on z being non-zero as y is now numeric(0) rather than the set
c(1,2,3). Why does R do this? Wouldn't it be more sensible for R to simply
leave the host set unchanged if there are no elements to take out?
No, it wouldn't. You asked for no entries, so you get no entries.
Follow Thierry's advice, and don't use which() unless you really need a
vector of indices, and are prepared for an empty one.
Duncan Murdoch
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
