Mike
see ?strip.custom and strip.default
Basically you need to create a string of factor levels equal to the number
of panels.
Below is an example for a plot of 24 panels 4 columns and six rows.
so that row 1 is:
"2000 Summer" | "2000 Autumn" | "2000 Winter" | "2000 Spring"
and so on for the remaining panel rows.
strip = strip.custom(factor.levels = c(paste(rep(2000:2005, each = 4),
rep(c("Summer","Autumn","Winter","Spring"),6),
sep = " ") ),
Use the xyplot layout argument to set up your layout properly to make it
easier.
If you want a 2 line strip then may be "\n" to break the paste into to 2
lines may do.
There was post about ?6 weeks ago on it I think
Regards
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
ARMIDALE NSW 2351
Email:
home: [EMAIL PROTECTED]
At 14:47 10/07/2008, you wrote:
Hi all,
By default a call to xyplot from the Lattice package when using 2
factors [eg xyplot( dv~iv | XY * AB ) ] yields the following shingle
structure:
|_A_|_A_|_B_|_B_|
|_X_|_Y_|_X_|_Y_|
However, I'm wondering if it is possible to merge the upper shingle
within levels of that factor, as in:
|___A___|___B___|
|_X_|_Y_|_X_|_Y_|
Mike
--
Mike Lawrence
Graduate Student, Department of Psychology, Dalhousie University
www.memetic.ca
"The road to wisdom? Well, it's plain and simple to express:
Err and err and err again, but less and less and less."
- Piet Hein
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