Hello,
I would add that it's probably better to assign
for(i in seq_along(file.names)){
A[[i]] <- extract_tables(file.names[i])
}
(It's a list so double [[, not just [).
Hope this helps,
Rui Barradas
Às 01:45 de 23/09/2018, Bert Gunter escreveu:
for(i in 1:length(file.names)){
A[i] <- extract_tables(file.names[i])}
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