Hello,
You have to get rid of the percent sign first. This can be done with ?sub
x <- "12.6%"
y <- sub("%$", "", x)
z <- as.numeric(y)
1) The dollar sign means "end of string". See ?regexpr.
2) You can all of that in one code line, no need to create y.
z <- as.numeric(sub("%$", "", x))
Hope this helps,
Rui Barradas
On 18/08/2018 22:20, Jeff Reichman wrote:
R-Help Forum
How do I convert a chr variable that contains percentages to an integer
Example 12.6% (chr) to 12.6 (int)
Jeff
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