Awesome, Sarah, thanks!
And thanks for the clarification about declaring the version of R.
Best,
Ibrahim
On Tue, 31 Jul 2018 at 13:50, Sarah Goslee <sarah.gos...@gmail.com> wrote:
> Hi,
>
> You need to tell R to look in the names component of your vector. Here
> are three different ways:
>
> vect <- c(foo = 11, bar = 2, norf = 45)
>
> vect[!(names(vect) %in% c("foo"))] # easily generalizable to a longer list
>
> vect[!grepl("foo", names(vect))]
>
> vect[!(names(vect) == "foo")]
>
> There are many more ways to do this, all predicated on matching a
> string within the character vector containing the names of your
> object.
>
> Also, on this list we don't care at all if you're using R Studio, or
> what the version is. We do potentially care what version of R itself
> you are using.
>
> Sarah
>
> On Tue, Jul 31, 2018 at 1:41 PM, إبراهيم خطاب Ibrauheem Khat'taub
> <barhomopo...@gmail.com> wrote:
> > H
> > i All,
> >
> > If I have this vector:
> >
> >> vect <- c(foo = 11, bar = 2, norf = 45)
> >
> > I can have a subset that has only "bar and "norf" this way:
> >> vect[c("bar","norf")]
> >
> > Now how do I achieve the same by asking it for a subset that simply
> > excludes "foo"? I tried all these, resulting in errors:
> >
> > vect[-"foo"]
> > vect[-c("foo")]
> > vect[!"foo"]
> > vect[!c("foo")]
> >
> > Thanks!
> >
>
>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>
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