Dear Thierry and Juan, thank you for your help. Thank you all.
Now, if I would like to add an element to the empty list, how shall I do :
for example, shall i = 2, and j = 1, in a bit of more complex R code :
x <- data.frame(TYPE=c("DEL", "DEL", "DUP", "TRA", "INV", "TRA"),
CHRA=c("chr1", "chr1", "chr1", "chr1", "chr2", "chr2"),
POSA=c(10, 15, 120, 340, 100, 220),
CHRB=c("chr1", "chr1", "chr1", "chr2", "chr2", "chr1"),
POSB=c(30, 100, 300, 20, 200, 320))
x$labA <- paste(x$CHRA, x$POSA, sep="_")
x$labB <- paste(x$CHRB, x$POSB, sep="_")
x$POSA_left <- x$POSA - 10
x$POSA_right <- x$POSA + 10
x$POSB_left <- x$POSB - 10
x$POSB_right <- x$POSB + 10
x$intersectA <- rep(list(list()), nrow(x))
x$intersectB <- rep(list(list()), nrow(x))
And we know that for i = 2, and j = 1, the condition is TRUE :
i <- 2
j <- 1
if ( (x$CHRA[i] == x$CHRA[j] ) &&
(x$POSA[i] > x$POSA_left[j] ) &&
(x$POSA[i] < x$POSA_right[j] ) ){
x$intersectA[i] <- c(x$intersectA[i], x$labA[j])}
the R code does not work. Thank you for your kind help !
On Wed, Jul 25, 2018 at 12:26 AM, Thierry Onkelinx <thierry.onkel...@inbo.be
> wrote:
> Dear Bogdan,
>
> You are looking for x$intersectA <- vector("list", nrow(x))
>
> Best regards,
>
>
> ir. Thierry Onkelinx
> Statisticus / Statistician
>
> Vlaamse Overheid / Government of Flanders
> INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND
> FOREST
> Team Biometrie & Kwaliteitszorg / Team Biometrics & Quality Assurance
> thierry.onkel...@inbo.be
> Havenlaan 88
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> 1000 Brussel
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>
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> than asking him to perform a post-mortem examination: he may be able to say
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> 2018-07-25 8:55 GMT+02:00 Bogdan Tanasa <tan...@gmail.com>:
>
>> Dear all,
>>
>> assuming that I do have a dataframe like :
>>
>> x <- data.frame(TYPE=c("DEL", "DEL", "DUP", "TRA", "INV", "TRA"),
>> CHRA=c("chr1", "chr1", "chr1", "chr1", "chr2", "chr2"),
>> POSA=c(10, 15, 120, 340, 100, 220),
>> CHRB=c("chr1", "chr1", "chr1", "chr2", "chr2", "chr1"),
>> POSB=c(30, 100, 300, 20, 200, 320)) ,
>>
>> how could I initiate another 2 columns in x, where each element in these 2
>> columns is going to be a list (the list could be updated later). Thank
>> you !
>>
>> Shall I do,
>>
>> for (i in 1:dim(x)[1]) { x$intersectA[i] <- list()}
>>
>> for (i in 1:dim(x)[1]) { x$intersectB[i] <- list()}
>>
>> nothing is happening. Thank you very much !
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posti
>> ng-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
[[alternative HTML version deleted]]
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