It would help if you show exactly the structure of your desired result, using
the simple example data you supplied (what, exactly, do you mean by "array"?)
If you want mydata[[1]] "to provide the values for all three 3 variables (Y, X1
and X2) of the first imputation only" then this will do it:
> mydat <- list( Imputed[1:8,] , Imputed[9:16,] )
> mydat[[1]]
X1 X2 Y
1 1 0 1
2 2 1 2
3 1 0 3
4 2 1 4
5 1 1 5
6 2 1 6
7 1 0 7
8 2 1 8
But mydata is not an array, it's a list.
The "[[ ]]" syntax doesn't particularly make sense on an array object:
> array(1:12, dim=c(2,3,2))
, , 1
[,1] [,2] [,3]
[1,] 1 3 5
[2,] 2 4 6
, , 2
[,1] [,2] [,3]
[1,] 7 9 11
[2,] 8 10 12
>
> array(1:12, dim=c(2,3,2))[[1]]
[1] 1
But "[[ ]]" does make sense on a list object.
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
Lab cell 925-724-7509
On 5/24/18, 8:14 AM, "R-help on behalf of Ioanna Ioannou"
<r-help-boun...@r-project.org on behalf of ii54...@msn.com> wrote:
Hello everyone,
Thank you for this. Nonetheless it is not exactly want i need.
I need mydata[[1]] to provide the values for all 3 variables (Y, X1 and X2)
of the first imputation only. As it stands it returns the whole database.
Any ideas?
Best,
ioanna
________________________________
From: Bert Gunter <bgunter.4...@gmail.com>
Sent: 24 May 2018 16:04
To: Ioanna Ioannou
Cc: r-help@r-project.org
Subject: Re: [R] Manipulation of data.frame into an array
This is one of those instances where a less superficial knowledge of R's
technical details comes in really handy.
What you need to do is convert the data frame to a single (numeric) vector
for, e.g. a matrix() call. This can be easily done by noting that a data frame
is also a list and using do.call():
## imp is the data frame:
do.call(c,imp)
X11 X12 X13 X14 X15 X16 X17 X18 X19 X110 X111 X112 X113 X114
1 2 1 2 1 2 1 2 1 2 1 2 1 2
X115 X116 X21 X22 X23 X24 X25 X26 X27 X28 X29 X210 X211 X212
1 2 0 1 0 1 1 1 0 1 0 1 0 1
X213 X214 X215 X216 Y1 Y2 Y3 Y4 Y5 Y6 Y7 Y8 Y9 Y10
1 1 0 1 1 2 3 4 5 6 7 8 1 2
Y11 Y12 Y13 Y14 Y15 Y16
3 4 5 6 7 8
So, e.g. for a 3 column matrix:
> matrix(do.call(c,imp), ncol=3)
[,1] [,2] [,3]
[1,] 1 0 1
[2,] 2 1 2
[3,] 1 0 3
[4,] 2 1 4
[5,] 1 1 5
[6,] 2 1 6
[7,] 1 0 7
[8,] 2 1 8
[9,] 1 0 1
[10,] 2 1 2
[11,] 1 0 3
[12,] 2 1 4
[13,] 1 1 5
[14,] 2 1 6
[15,] 1 0 7
[16,] 2 1 8
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, May 24, 2018 at 7:46 AM, Ioanna Ioannou
<ii54...@msn.com<mailto:ii54...@msn.com>> wrote:
Hello everyone,
I want to transform a data.frame into an array (lets call it mydata),
where: mydata[[1]] is the first imputed dataset...and for each mydata[[d]], the
first p columns are covariates X, and the last one is the outcome Y.
Lets assume a simple data.frame:
Imputed = data.frame( X1 = c(1,2,1,2,1,2,1,2, 1,2,1,2,1,2,1,2),
X2 = c(0,1,0,1,1,1,0,1,
0,1,0,1,1,1,0,1),
Y =
c(1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8))
The first 8 have been obtained by the first imputation and the later 8 by
the 2nd.
Can you help me please?
Best,
ioanna
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