> On May 22, 2018, at 10:57 PM, John <miao...@gmail.com> wrote:
>
> Thanks, David.
> I got the answer from the web.
> Is there any easy way to permute a set (e.g., a set of characters) by the
> permutation it returns? Thanks,
>
>
> > x <- c(10,7,4,3,8,2)
> > sort(x, index.return=TRUE)
> $x
> [1] 2 3 4 7 8 10
>
> $ix
> [1] 6 4 3 2 5 1
>
I don't understand what is being requested. The $ix value is the same as the
one returned `by order`.
David.
> 2018-05-23 10:49 GMT+08:00 David Winsemius <dwinsem...@comcast.net>:
>
>
> > On May 22, 2018, at 10:06 PM, John <miao...@gmail.com> wrote:
> >
> > Hi,
> >
> > Is there any way to find the permutation function of the sorting and to
> > apply the function (or its inverse) elsewhere?
> >
> > For example, the following permutation function from the sorting in the
> > matrix form is
> > c(1,2,3), c(2,1,3)
> >
> >> sort(c("bc","ac","dd"))
> > [1] "ac" "bc" "dd"
> >
>
> I think you are asking for the `order` function.
>
> > I try to find it in the permutations/permute package, but I can't find it
> >
> > John
> >
> > [[alternative HTML version deleted]]
>
>
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