I would use
sub("\\(.*\\)", "()", s)
It is essentially the same as Rui's suggestion, but I find the purpose to
be more clear. It might also be a little more efficient.
HTH
Ulrik
On Mon, 21 May 2018, 15:38 Rui Barradas, <ruipbarra...@sapo.pt> wrote:
> Hello,
>
> Try this.
>
>
> ss1 <- "z:f(5, a=3, b=4, c='1:4', d=2)"
> ss2 <- "f(5, a=3, b=4, c=\"1:4\", d=2)*z"
>
> fun <- function(s) sub("(\\().*(\\))", "\\1\\2", s)
>
> fun(ss1)
> #[1] "z:f()"
>
> fun(ss2)
> #[1] "f()*z"
>
>
> Hope this helps,
>
> Rui Barradas
>
> On 5/21/2018 2:33 PM, Vito M. R. Muggeo wrote:
> > dear all,
> > I am stuck on the following problem. Give a string like
> >
> > ss1<- "z:f(5, a=3, b=4, c='1:4', d=2)"
> >
> > or
> >
> > ss2<- "f(5, a=3, b=4, c=\"1:4\", d=2)*z"
> >
> > I would like to remove all entries within parentheses.. Namely, I aim to
> > obtain respectively
> >
> > "z:f()" or "f()*z"
> >
> > I played with sub() and gsub() but without success..
> > Thank you very much for your time,
> >
> > best,
> > vito
> >
> >
>
> ______________________________________________
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