"I see: consistency with additive identity. " Ummm, well:
> 1+NULL numeric(0) > sum(1,NULL) [1] 1 Of course, there could well be something here I don't get, but that doesn't look very consistent to me. However, as I said privately, so long as the corner case behavior is documented, which it is, I don't care. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, Mar 21, 2018 at 10:26 AM, Boris Steipe <boris.ste...@utoronto.ca> wrote: > I see: consistency with additive identity. That makes sense. Thanks. > > B. > > > > On Mar 21, 2018, at 1:22 PM, peter dalgaard <pda...@gmail.com> wrote: > > > > No. The empty sum is zero. Adding it to another sum should not change > it. Nothing audacious about that. This is consistent; other definitions > just cause trouble. > > > > -pd > > > >> On 21 Mar 2018, at 18:05 , Boris Steipe <boris.ste...@utoronto.ca> > wrote: > >> > >> Surely the result of summation of non-existent values is not defined, > is it not? And since the NA values have been _removed_, there's nothing > left to sum over. In fact, pretending the the result in that case is zero > would appear audacious, no? > >> > >> Cheers, > >> Boris > >> > >> > >> > >> > >> > >>> On Mar 21, 2018, at 12:58 PM, Jeff Newmiller <jdnew...@dcn.davis.ca.us> > wrote: > >>> > >>> What do you mean by "should not"? > >>> > >>> NULL means "missing object" in R. The result of the sum function is > always expected to be numeric... so NA_real or NA_integer could make sense > as possible return values. But you cannot compute on NULL so no, that > doesn't work. > >>> > >>> See the note under the "Value" section of ?sum as to why zero is > returned when all inputs are removed. > >>> -- > >>> Sent from my phone. Please excuse my brevity. > >>> > >>> On March 21, 2018 9:03:29 AM PDT, Boris Steipe < > boris.ste...@utoronto.ca> wrote: > >>>> Should not the result be NULL if you have removed the NA with > >>>> na.rm=TRUE ? > >>>> > >>>> B. > >>>> > >>>> > >>>> > >>>>> On Mar 21, 2018, at 11:44 AM, Stefano Sofia > >>>> <stefano.so...@regione.marche.it> wrote: > >>>>> > >>>>> Dear list users, > >>>>> let me ask you this trivial question. I worked on that for a long > >>>> time, by now. > >>>>> Suppose to have a data frame with NAs and to sum some columns with > >>>> rowSums: > >>>>> > >>>>> df <- data.frame(A = runif(10), B = runif(10), C = rnorm(10)) > >>>>> df[1, ] <- NA > >>>>> rowSums(df[ , which(names(df) %in% c("A","B"))], na.rm=T) > >>>>> > >>>>> If all the elements of the selected columns are NA, rowSums returns 0 > >>>> while I need NA. > >>>>> Is there an easy and efficient way to use rowSums within a function > >>>> like > >>>>> > >>>>> function(x) ifelse(all(is.na(x)), as.numeric(NA), rowSums...)? > >>>>> > >>>>> or an equivalent function? > >>>>> > >>>>> Thank you for your help > >>>>> Stefano > >>>>> > >>>>> > >>>>> > >>>>> (oo) > >>>>> --oOO--( )--OOo---------------- > >>>>> Stefano Sofia PhD > >>>>> Area Meteorologica e Area nivologica - Centro Funzionale > >>>>> Servizio Protezione Civile - Regione Marche > >>>>> Via del Colle Ameno 5 > >>>>> 60126 Torrette di Ancona, Ancona > >>>>> Uff: 071 806 7743 > >>>>> E-mail: stefano.so...@regione.marche.it > >>>>> ---Oo---------oO---------------- > >>>>> > >>>>> ________________________________ > >>>>> > >>>>> AVVISO IMPORTANTE: Questo messaggio di posta elettronica può > >>>> contenere informazioni confidenziali, pertanto è destinato solo a > >>>> persone autorizzate alla ricezione. 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