> On Feb 12, 2018, at 6:22 PM, Dennis Fisher <fis...@plessthan.com> wrote:
>
> R 3.4.2
> OS X
>
> Colleagues
>
> I would appreciate some help with regular expressions.
>
> I have string that looks like:
> " ITERATION ,THETA1 ,THETA2
> ,THETA3 ,THETA4 ,THETA5
> ,THETA6 ,THETA7 ,SIGMA(1,1)
> ,SIGMA(2,1) ,SIGMA(2,2)”
>
> In the entries that contain:
> (X,Y) # for example, SIGMA(1,1)
> I would like to replace the comma with a period, e.g., SIGMA(1.1) but NOT the
> other commas
>
> The end-result would be:
> " ITERATION ,THETA1 ,THETA2
> ,THETA3 ,THETA4 ,THETA5
> ,THETA6 ,THETA7 ,SIGMA(1.1)
> ,SIGMA(2.1) ,SIGMA(2.2)”
>
> Can someone provide the regular expression code to accomplish this?
gsub( "([(]\\d+)([,])(\\d+[)])", "\\1.\\3", x)\
#-----------
[1] "ITERATION ,THETA1 ,THETA2
,THETA3 ,THETA4 ,THETA5 ,THETA6
,THETA7 ,SIGMA(1.1) ,SIGMA(2.1)
,SIGMA(2.2)"
> Thanks.
>
> Dennis
>
> Dennis Fisher MD
> P < (The "P Less Than" Company)
> Phone / Fax: 1-866-PLessThan (1-866-753-7784)
> www.PLessThan.com
>
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David Winsemius
Alameda, CA, USA
'Any technology distinguishable from magic is insufficiently advanced.'
-Gehm's Corollary to Clarke's Third Law
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