Hello,

I believe the following is simpler.
It changes the OP's code a bit and uses lapply, not apply.


res2 <- lapply(C, fitdist, "gamma")
do.call(rbind, lapply(res2, `[[`, "estimate"))
#      shape     rate
#A  3.702253 1.234126
#B 31.300800 3.912649


Hope this helps,

Rui Barradas

On 1/29/2018 10:25 AM, Eric Berger wrote:
Capture the results of the apply command into an object and then work with
that. Here is one way to do it:

res <- apply(C, 2, fitdist, "gamma")
out <- c( res$A$estimate["shape"], res$B$estimate["shape"],
res$A$estimate["rate"], res$B$estimate["rate"])
names(out) <- c("A shape","B shape","A rate","B Rate")
print(out)

#   A shape   B shape    A rate    B Rate
# 3.702253 31.300800  1.234126  3.912649

HTH,
Eric


On Mon, Jan 29, 2018 at 10:25 AM, smart hendsome via R-help <
r-help@r-project.org> wrote:

Hi,
Let say I have data by two columns A and B, and I have fit each column
using the gamma distribution by 'fitdist' . I just want the result show
only the shape and rate only.

Eg:
library(fitdistrplus)

A <-c(1,2,3,4,5)

B<-c(6,7,8,9,10)

C <-cbind(A,B)
apply(C, 2, fitdist, "gamma")
Output show like this:
$A
Fitting of the distribution ' gamma ' by maximum likelihood
Parameters:
       estimate Std. Error
shape 3.702253  2.2440052
rate  1.234126  0.8011369

$B
Fitting of the distribution ' gamma ' by maximum likelihood
Parameters:
        estimate Std. Error
shape 31.300800   19.69176
rate   3.912649    2.48129

I want the output to be like this:
                  A                    B
  shape 3.702253  31.300800rate  1.234126  3.912649
Can anyone solve my problem? Many thanks.

Regards,
Zuhri




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