Solve for one of your variables and it will be given in terms of the other two. That is, there is a whole infinite plane of solutions. No, aggregate will not be sufficient to enumerate the solution set.. -- Sent from my phone. Please excuse my brevity.
On December 7, 2017 10:37:37 PM PST, Benjamin Sabatini <sunsca...@hotmail.com> wrote: >Hi, > >I'm trying to find a way to determine what multiples of the combination >of three or more numbers equals a forth number. > >So, if I had a number set like: > >c(13.4689, 12.85212, 17.05071) > >What combination and multiples of these numbers would average to >15.0078? (so, something that would tell me x, y, and z in (x*13.4689 + >y*12.85212+ z*17.05071) / x+y+z) = 15.0078 > >I think this is doable with aggregate? > > [[alternative HTML version deleted]] This is a plain text mailing list. Please learn how to use your email program. > >______________________________________________ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
