Until I get a fix that works, a work-around would be to rename the 'y1' column,
used a fixed formula, and rename it back afterwards.
Thanks for your help.
SGO.
-----Original Message-----
From: Bert Gunter [mailto:bgunter.4...@gmail.com]
Sent: 22 August 2017 20:38
To: Stephen O'hagan <soha...@manchester.ac.uk>
Cc: r-help@r-project.org
Subject: Re: [R] boot.stepAIC fails with computed formula
OK, here's the problem. Continuing with your example:
strt1 <- lm(y1 ~1, dat)
strt2 <- lm(frm1,dat)
strt1
Call:
lm(formula = y1 ~ 1, data = dat)
Coefficients:
(Intercept)
41.73
strt2
Call:
lm(formula = frm1, data = dat)
Coefficients:
(Intercept)
41.73
Note that the formula objects of the lm object are different: strt2 does not
evaluate the formula. So presumably boot.step.AIC does no evaluation and
therefore gets confused with the errors you saw. So you need to get the
evaluated formula into the lm object. This can be done, e.g. via:
strt2 <- eval(substitute(lm(form,data = dat), list(form = frm1)))
## yielding
strt2
Call:
lm(formula = y1 ~ 1, data = dat)
Coefficients:
(Intercept)
41.73
So this looks like it should fix the problem, but alas no, the boot.stepAIC
call still fails with the same error message. Here's why:
identical(strt$call, strt2$call)
[1] FALSE
So one might rightfully ask, what the heck is going on here?! Further digging:
str(strt$call)
language lm(formula = y1 ~ 1, data = dat)
str(strt2$call)
language lm(formula = y1 ~ 1, data = dat)
These certainly look identical! -- but of course they're not:
names(strt$call)
[1] "" "formula" "data"
names(strt2$call)
[1] "" "formula" "data"
So the difference must lie in the formula component, right? ...
strt$call$formula
y1 ~ 1
strt2$call$formula
y1 ~ 1
So, thus far, huhh? But..
class(strt2$call$formula)
[1] "formula"
class(strt$call$formula)
[1] "call"
So I think therein lies the critical difference that is screwing things up.
NOTE: If I am wrong about this someone **PLEASE** correct me.
I see no clear workaround for this other than to explicitly avoid
passing a formula in the lm() call with y~1 or y ~ . I think the
real fix is to make the boot.stepAIC function smarter in how it handles its
formula argument, and that is above my paygrade (and degree of interest) . You
should probably email the maintainer, who may not monitor this list. But give
it a day or so to give someone else a chance to correct me if I'm wrong.
HTH.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and sticking
things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Aug 22, 2017 at 8:17 AM, Stephen O'hagan <soha...@manchester.ac.uk>
wrote:
I'm trying to use boot.stepAIC for feature selection; I need to be able to
specify the name of the dependent variable programmatically, but this appear to
fail:
In R-Studio with MS R Open 3.4:
library(bootStepAIC)
#Fake data
n<-200
x1 <- runif(n, -3, 3)
x2 <- runif(n, -3, 3)
x3 <- runif(n, -3, 3)
x4 <- runif(n, -3, 3)
x5 <- runif(n, -3, 3)
x6 <- runif(n, -3, 3)
x7 <- runif(n, -3, 3)
x8 <- runif(n, -3, 3)
y1 <- 42+x3 + 2*x6 + 3*x8 + runif(n, -0.5, 0.5)
dat <- data.frame(x1,x2,x3,x4,x5,x6,x7,x8,y1)
#the real data won't have these names...
cn <- names(dat)
trg <- "y1"
xvars <- cn[cn!=trg]
frm1<-as.formula(paste(trg,"~1"))
frm2<-as.formula(paste(trg,"~ 1 + ",paste(xvars,collapse = "+")))
strt=lm(y1~1,dat) # boot.stepAIC Works fine
#strt=do.call("lm",list(frm1,data=dat)) ## boot.stepAIC FAILS ##
#strt=lm(frm1,dat) ## boot.stepAIC FAILS ##
limit<-5
stp=stepAIC(strt,direction='forward',steps=limit,
scope=list(lower=frm1,upper=frm2))
bst <- boot.stepAIC(strt,dat,B=50,alpha=0.05,direction='forward',steps=limit,
scope=list(lower=frm1,upper=frm2))
b1 <- bst$Covariates
ball <- data.frame(b1)
names(ball)=unlist(trg)
Any ideas?
Cheers,
SOH
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