This is pretty close to your original plot. To get clockwise we multiply the
radians by -1 and then add pi/2 to move the origin to 12 o'clock. We need to
flip the start and end values since now we are be plotting from the end to the
start:
start<-c(1,5,600,820)
end<-c(250,75,810,1200)
score<-c(7,-1,4,-6.5)
dat<-data.frame(start=start,end=end,score=score,col="blue",stringsAsFactors=F)
dat[dat$score<0,]$col<-"red"
# Convert begin/stop to radians
dat$stop <- -(2 * pi * dat$start/1500) + pi/2
dat$begin <- -(2 * pi * dat$end/1500) + pi/2
# Open blank plot window and draw circles
Canvas(xlim = c(-5,5), xpd=TRUE)
DrawCircle (r.out = 5, r.in = 5, theta.1=pi/2+.05, theta.2=pi*5/2-.05, lwd=3)
with(dat, DrawCircle(r.out = 5 - score/5, r.in = 5 - score/5,
theta.1= begin, theta.2= stop, border=col, lwd=4))
text(.1, 5.5, "1", pos=4)
text(-.1, 5.5, "1500", pos=2)
David C
From: swaraj basu [mailto:projectb...@gmail.com]
Sent: Monday, February 13, 2017 3:58 PM
To: David L Carlson <dcarl...@tamu.edu>; r-help@r-project.org
Subject: Re: [R] Circular plot
Thank you David, I could get the circle at 12 and clockwise however I believe
my solution is not the optimal one, could you help me out with the best way to
generate the circle clockwise at 12 and then convert the begin/stop to radians
Here is what I tried
par(mar=c(2,2,2,2),xpd=TRUE);
plot(c(1,800),c(1,800),type="n",axes=FALSE,xlab="",ylab="",main="");
DrawCircle (x=400,y=400,r.out = 400, r.in = 400, theta.1=1.57,
theta.2=-2*pi-4.67, lwd=1)
On Mon, Feb 13, 2017 at 6:52 PM, David L Carlson <dcarl...@tamu.edu> wrote:
You can do this easily with the DrawCircle() function in package DescTools. It
is easiest to use geometric coordinates (0 is at 3 o'clock and moves
counterclockwise around the circle), but it could be converted to 12 o'clock
and clockwise:
library(DescTools)
# Convert begin/stop to radians
dat$begin <- 0 + 2 * pi * dat$start/1500
dat$stop <- 0 + 2 * pi * dat$end/1500
# Open blank plot window and draw circles
Canvas(xlim = c(-5,5), xpd=TRUE)
DrawCircle (r.out = 5, r.in = 5, theta.1=.05, theta.2=2*pi-.05, lwd=3)
with(dat, DrawCircle(r.out = 5 - score/5, r.in = 5 - score/5,
theta.1=begin, theta.2=stop, border=col, lwd=4))
text(5.2, .4, "1", pos=4)
text(5.2, -.4, "1500", pos=4)
-------------------------------------
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-----Original Message-----
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of swaraj basu
Sent: Monday, February 13, 2017 10:34 AM
To: r-help@r-project.org
Subject: [R] Circular plot
I want to plot segments deleted from mitochondrial DNA of patients with
neuromuscular disorders. I generate the plot on a linear chromosome using a
code similar to as shown below
start<-c(1,5,600,820)
end<-c(250,75,810,1200)
score<-c(7,-1,4,-6.5)
dat<-data.frame(start=start,end=end,score=score,col="blue",stringsAsFactors=F)
dat[dat$score<0,]$col<-"red"
plot(1:1500,rep(0,1500),type="p",ylim=c(-10,10),col="white",xlab="position",ylab="score")
segments(dat$start, dat$score, dat$end, dat$score, col=dat$col, lwd=3)
Since the human mitochondria is a circular genome, I would like to
visualise the plot generated above as a circle where all segments with
positive score lie inside the circle and those with negative score lie
outside. Attached is a representation of my requirement, although here it
is manually drawn. Can someone help me on this?
--
Swaraj Basu
--
Swaraj Basu
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