Hi Ana,
Here is one way:
pathway1<-LETTERS[1:5]
pathway2<-c("A","C","F")
pathway3<-c("B","D","E")
intersect.mat<-matrix(0,nrow=3,ncol=3)
rownames(intersect.mat)<-paste("pathway",1:3,sep="")
colnames(intersect.mat)<-paste("pathway",1:3,sep="")
for(row in 1:3) {
for(col in 1:3)
intersect.mat[row,col]<-
sum(get(rownames(intersect.mat)[row])%in%
get(colnames(intersect.mat)[col]))
}
Jim
On Fri, Feb 3, 2017 at 6:54 AM, Li, Aiguo (NIH/NCI) [E]
<l...@mail.nih.gov> wrote:
> Dear all,
>
> I am new to r script and run into some difficulty with this simple task.
> Here is my data: I need to find out the number of mutual intersected elements
> as shown below
> data
> pathway1 A B C D
> E
> pathway2 A C F
> pathway3 B D E
>
> output
> pathway1 pathway2
> pathway3
> pathway1 5 2
> 3
> pathway2 2 3
> 0
> pathway3 3 0
> 3
>
> here is my script
> tb = matrix(data =NA, nrow = 3, ncol = 3)
> for(i in 1:3){
> for(j in 1:3){
>
> tb[i,j]=length(intersect(data[i,][!is.na(data[i,])],
> data[j,][!is.na(data[j,])]))
> }
> }
>
> Ana
>
> [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
