There are well-informed answers given as examples on the sub() help page.
Hint 1: there is no need to globally substitute patterns anchored at the
end: they can only match in one place. There is also no need to
substitute "" for "".
Hint 2: 'blank characters' and 'spaces' are not the same thing.
[:blank:] seems the relevant character class, so
sub("[[:blank:]]+$", "", x)
seems an accurate answer to the question asked (which might not be the
question intended).
On Fri, 27 Jun 2008, john seers (IFR) wrote:
There is also the "trim" command in the gdata package. Removes blanks
from the front of the string as well which may not be what you want.
But that removes *spaces* and not *blanks*, according to the help page
(and the actual code -- in fact it removes only ASCII space characters
and not others such as nbspace).
Regards
JS
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of jim holtman
Sent: 27 June 2008 10:27
To: juli pausas
Cc: R-help
Subject: Re: [R] removing blanks from a string
Is this what you want:
x <- c("hola ", "Yes ", "hello ")
gsub(" *$", "", x)
[1] "hola" "Yes" "hello"
On Fri, Jun 27, 2008 at 4:34 AM, juli pausas <[EMAIL PROTECTED]> wrote:
Hi
Is there a way to remove blank characters from the end of strings in a
vector? Something like the =TRIM functions of the OpenOffice
spreadsheet. E.g.,
a <- c("hola ", "Yes ", "hello ") # I'd like to get:
c("hola", "Yes", "hello")
Thanks
Juli
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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