Many Thanks,
What is exactly the solution.
Best,
Karim
On Sun, Nov 20, 2016 at 8:17 PM, David Winsemius <dwinsem...@comcast.net>
wrote:
>
> > On Nov 20, 2016, at 11:11 AM, David Winsemius <dwinsem...@comcast.net>
> wrote:
> >
> >
> >> On Nov 20, 2016, at 10:49 AM, Karim Mezhoud <kmezh...@gmail.com> wrote:
> >>
> >> Yes the results does not have a date but
> >> successive DCE.1, DCE2, DCE.3 indicates
> >> DCE.date1 , DCE.date2, DCE.date3
> >> I hope that the chronological order of date is conserved.
> >
> > There are, however, 4 dates. See this pair of results. You can probably
> do something if you ever figure out what it is that you precisely want. I
> think the date ordering is automatic here:
> >
> >> require(reshape2)
> > Loading required package: reshape2
> >
> >> dcast(dat, first.Name + Name + Department ~ date, value.var='DCE')
> > first.Name Name Department 2013-09-30 2013-12-28 2014-03-30
> 2014-06-28
> > 1 Amish Wives TAS 0.59 NA 0.59
> NA
> > 2 Ancient Nation QLH 0.54 0.28 0.54
> 0.28
> > 3 Auction Videos YME 0.57 NA 0.57
> NA
> >> dcast(dat, first.Name + Name + Department ~ date, value.var='DP')
> > first.Name Name Department 2013-09-30 2013-12-28 2014-03-30 2014-06-28
> > 1 Amish Wives TAS 0.56 NA 0.56
> NA
> > 2 Ancient Nation QLH 0.58 0.29 0.58
> 0.29
> > 3 Auction Videos YME 0.56 NA 0.56
> NA
>
> Yjos completes the process in the reshape2 world:
>
> > mdat <- melt(dat, measure.vars=c("DCE", 'DP') )
> > str(mdat)
> 'data.frame': 24 obs. of 6 variables:
> $ first.Name: Factor w/ 48 levels "Amish","Ancient",..: 3 1 2 3 1 2 3 1 2
> 3 ...
> $ Name : Factor w/ 48 levels "Aliens","Behavior",..: 43 47 29 43 47
> 29 43 47 29 43 ...
> $ Department: Factor w/ 8 levels "HXW","QLH","RAR",..: 8 6 2 8 6 2 8 6 2
> 8 ...
> $ date : Date, format: "2013-09-30" "2013-09-30" ...
> $ variable : Factor w/ 2 levels "DCE","DP": 1 1 1 1 1 1 1 1 1 1 ...
> $ value : num 0.57 0.59 0.54 NA NA 0.28 0.57 0.59 0.54 NA ...
>
> > dcast(mdat, first.Name + Name + Department ~ date+variable )
> first.Name Name Department 2013-09-30_DCE 2013-09-30_DP 2013-12-28_DCE
> 1 Amish Wives TAS 0.59 0.56 NA
> 2 Ancient Nation QLH 0.54 0.58 0.28
> 3 Auction Videos YME 0.57 0.56 NA
> 2013-12-28_DP 2014-03-30_DCE 2014-03-30_DP 2014-06-28_DCE 2014-06-28_DP
> 1 NA 0.59 0.56 NA NA
> 2 0.29 0.54 0.58 0.28 0.29
> 3 NA 0.57 0.56 NA NA
>
> --
> David.
>
> >
> >
> >
> >> Thanks,
> >> Karim
> >>
> >>
> >> On Sun, Nov 20, 2016 at 7:44 PM, David Winsemius <
> dwinsem...@comcast.net> wrote:
> >>
> >>> On Nov 20, 2016, at 5:28 AM, Karim Mezhoud <kmezh...@gmail.com> wrote:
> >>>
> >>> Sorry for the delay,
> >>> Many Thanks for Mr. David and Mr. Petr
> >>> I thinked to use "sort" function to arrange chronologically value
> by 'date' (without 'date' is colnames) of each variables (DCE, DP).
> >>>
> >>>
> >>> The solution of David seems to be simple to understand with "unlist"
> function.
> >>> The solution of Petr seems to be fancy. I did not find document about
> "I" argument for aggregate function.
> >>>
> >>> How can know which value for which date?
> >>
> >> You asked for a functional reshaping that did not have the date. Now
> you want the date? There was no date in the result you indicated was
> desired. ....??????
> >>
> >> --
> >> David.
> >>
> >>>
> >>> I will save the reshaping/ordering dataframe for later use.
> >>> Many Thanks,
> >>> Karim
> >>>
> >>>
> >>> On Fri, Nov 18, 2016 at 11:34 AM, PIKAL Petr <petr.pi...@precheza.cz>
> wrote:
> >>> Hi
> >>>
> >>> same result can be achieved by
> >>>
> >>> dat.ag<-aggregate(dat[ , c("DCE","DP")], by= list(dat$first.Name,
> dat$Name, dat$Department) , "I")
> >>>
> >>> Sorting according to the first row seems to be quite tricky. You could
> probably get closer by using some combination of split and order and
> arranging back chunks of data
> >>>
> >>> ooo1<-order(split(dat$DCE,interaction(dat$first.Name, dat$Name,
> dat$Department, drop=T))[[1]])
> >>> data.frame(sapply(split(dat$DCE,interaction(dat$first.Name, dat$Name,
> dat$Department, drop=T)), rbind))[ooo1,]
> >>> Ancient.Nation.QLH Amish.Wives.TAS Auction.Videos.YME
> >>> 2 0.28 NA NA
> >>> 4 0.28 NA NA
> >>> 1 0.54 0.59 0.57
> >>> 3 0.54 0.59 0.57
> >>>
> >>> however I wonder why the order according to the first row is necessary
> if all NAs are on correct positions?
> >>>
> >>> Cheers
> >>> Petr
> >>>
> >>>
> >>>> -----Original Message-----
> >>>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of David
> >>>> Winsemius
> >>>> Sent: Friday, November 18, 2016 9:30 AM
> >>>> To: Karim Mezhoud <kmezh...@gmail.com>
> >>>> Cc: r-help@r-project.org
> >>>> Subject: Re: [R] aggregate dataframe by multiple factors
> >>>>
> >>>>
> >>>>> On Nov 17, 2016, at 11:27 PM, Karim Mezhoud <kmezh...@gmail.com>
> >>>> wrote:
> >>>>>
> >>>>> Dear all,
> >>>>>
> >>>>> the dat has missing values NA,
> >>>>>
> >>>>> first.Name Name Department DCE DP date
> >>>>> 5 Auction Videos YME 0.57 0.56 2013-09-30
> >>>>> 18 Amish Wives TAS 0.59 0.56 2013-09-30
> >>>>> 34 Ancient Nation QLH 0.54 0.58 2013-09-30
> >>>>> 53 Auction Videos YME NA NA 2013-12-28
> >>>>> 66 Amish Wives TAS NA NA 2013-12-28
> >>>>> 82 Ancient Nation QLH 0.28 0.29 2013-12-28
> >>>>> 102 Auction Videos YME 0.57 0.56 2014-03-30
> >>>>> 115 Amish Wives TAS 0.59 0.56 2014-03-30
> >>>>> 131 Ancient Nation QLH 0.54 0.58 2014-03-30
> >>>>> 150 Auction Videos YME NA NA 2014-06-28
> >>>>> 163 Amish Wives TAS NA NA 2014-06-28
> >>>>> 179 Ancient Nation QLH 0.28 0.29 2014-06-28
> >>>>>
> >>>>>
> >>>>> agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> >>>>> list(dat$first.Name, dat$Name, dat$Department) , "sort"))
> >>>>
> >>>> The closest I could get on a few attempts was:
> >>>>
> >>>> (agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> >>>> list(dat$first.Name, dat$Name, dat$Department) , function(d) {
> unlist(d)}))
> >>>> )
> >>>>
> >>>> Group.1 Group.2 Group.3 DCE.1 DCE.2 DCE.3 DCE.4 DP.1 DP.2 DP.3 DP.4
> >>>> 1 Ancient Nation QLH 0.54 0.28 0.54 0.28 0.58 0.29 0.58 0.29
> >>>> 2 Amish Wives TAS 0.59 NA 0.59 NA 0.56 NA 0.56 NA
> >>>> 3 Auction Videos YME 0.57 NA 0.57 NA 0.56 NA 0.56 NA
> >>>>
> >>>> I think the sort operation might be somewhat ambiguous in this
> instance. I
> >>>> tried:
> >>>>
> >>>> (agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> >>>> list(dat$first.Name, dat$Name, dat$Department) , function(d) {
> >>>> unlist(lapply(d,sort))}))
> >>>> )
> >>>>
> >>>> With no success, not even a sorted result.
> >>>>
> >>>> --
> >>>> David.
> >>>>>
> >>>>>
> >>>>> agg has list of value. I would separate value in different columns.
> >>>>>
> >>>>> Group.1 Group.2 Group.3 DCE DP
> >>>>> 1 Ancient Nation QLH 0.28, 0.28, 0.54, 0.54 0.29, 0.29, 0.58,
> 0.58
> >>>>> 2 Amish Wives TAS 0.59, 0.59 0.56,
> 0.56
> >>>>> 3 Auction Videos YME 0.57, 0.57 0.56,
> 0.56
> >>>>>
> >>>>> The goal:
> >>>>>
> >>>>> Group.1 Group.2 Group.3 DCE.1 DCE.2 DCE.3 DCE.4 DP.1 DP.2 DP.3
> DP.4
> >>>>> 1 Ancient Nation QLH 0.28 0.28 0.54 0.54
> 0.29, 0.29,
> >>>>> 0.58, 0.58
> >>>>> 2 Amish Wives TAS NA NA 0.59, 0.59
> NA
> >>>>> NA 0.56, 0.56
> >>>>> 3 Auction Videos YME NA NA 0.57, 0.57
> NA
> >>>>> NA 0.56, 0.56
> >>>>>
> >>>>>
> >>>>>
> >>>>> dat <- structure(list(first.Name = structure(c(3L, 1L, 2L, 3L, 1L,
> 2L,
> >>>>> 3L, 1L, 2L, 3L, 1L, 2L), .Label = c("Amish", "Ancient", "Auction",
> >>>>> "Ax", "Bachelorette", "Basketball", "BBQ", "Cake", "Celebrity",
> >>>>> "Chef", "Clean", "Colonial", "Comedy", "Comic", "Crocodile", "Dog",
> >>>>> "Empire", "Extreme", "Farm", "Half Pint", "Hollywood", "House", "Ice
> >>>>> Road", "Jersey", "Justice", "Love", "Mega", "Model", "Modern",
> >>>>> "Mountain", "Mystery", "Myth", "New York", "Paradise", "Pioneer",
> >>>>> "Queer", "Restaurant", "Road", "Royal", "Spouse", "Star", "Storage",
> >>>>> "Survival", "The Great American", "Tool", "Treasure", "Wedding",
> >>>>> "Wife"), class = "factor"), Name = structure(c(43L, 47L, 29L, 43L,
> >>>>> 47L, 29L, 43L, 47L, 29L, 43L, 47L, 29L), .Label = c("Aliens",
> >>>>> "Behavior", "Casino", "Casting Call", "Challenge", "Contest",
> >>>>> "Crashers", "Crew", "Dad", "Dancing", "Date", "Disasters", "Dynasty",
> >>>>> "Family", "Garage", "Greenlight", "Gypsies", "Haul", "Hot Rod",
> >>>>> "Inventor", "Jail", "Job", "Justice", "Marvels", "Master", "Mates",
> >>>>> "Model", "Moms", "Nation", "Ninja", "Patrol", "People", "Pitmasters",
> >>>>> "Queens", "Rescue", "Rivals", "Room", "Rooms", "Rules", "Star",
> >>>>> "Stars", "Superhero", "Videos", "VIP", "Wars", "Wishes", "Wives",
> >>>>> "Wrangler"), class = "factor"), Department = structure(c(8L, 6L, 2L,
> >>>>> 8L, 6L, 2L, 8L, 6L, 2L, 8L, 6L, 2L), .Label = c("HXW", "QLH", "RAR",
> >>>>> "RYC", "SYI", "TAS", "VUV", "YME"), class = "factor"),
> >>>>> DCE = c(0.57, 0.59, 0.54, NA, NA, 0.28, 0.57, 0.59, 0.54,
> >>>>> NA, NA, 0.28), DP = c(0.56, 0.56, 0.58, NA, NA, 0.29, 0.56,
> >>>>> 0.56, 0.58, NA, NA, 0.29), date = structure(c(15978, 15978,
> >>>>> 15978, 16067, 16067, 16067, 16159, 16159, 16159, 16249, 16249,
> >>>>> 16249), class = "Date")), description = "", row.names = c(5L, 18L,
> >>>>> 34L, 53L, 66L, 82L, 102L, 115L, 131L, 150L, 163L, 179L), class =
> >>>>> "data.frame", .Names = c("first.Name", "Name", "Department", "DCE",
> >>>>> "DP", "date"))
> >>>>>
> >>>>> [[alternative HTML version deleted]]
> >>>>>
> >>>>> ______________________________________________
> >>>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> >>>>> PLEASE do read the posting guide
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> >>>>> and provide commented, minimal, self-contained, reproducible code.
> >>>>
> >>>> David Winsemius
> >>>> Alameda, CA, USA
> >>>>
> >>>> ______________________________________________
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> >> David Winsemius
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> >>
> >>
> >
> > David Winsemius
> > Alameda, CA, USA
> >
> > ______________________________________________
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