I'm still not clear about whether this is a bug in foreach. Should c.Date be
invoked by foreach with .combine='c'?
On 11/06/2016 07:02 PM, William Dunlap wrote:
Note that in the OP's example c.Date is never invoked. c.Date is called if
.combine
calls c rather than if .combine is c:
> library(zoo)
> trace(c.Date, quote(print(sys.call())))
Tracing function "c.Date" in package "base"
[1] "c.Date"
> foreach(i=10000:10003, .combine=c) %do% { as.Date(i) }
[1] 10000 10001 10002 10003
> foreach(i=10000:10003, .combine=function(...)c(...)) %do% { as.Date(i) }
Tracing c.Date(...) on entry
eval(expr, envir, enclos)
Tracing c.Date(...) on entry
eval(expr, envir, enclos)
Tracing c.Date(...) on entry
eval(expr, envir, enclos)
[1] "1997-05-19" "1997-05-20" "1997-05-21" "1997-05-22"
Bill Dunlap
TIBCO Software
wdunlap tibco.com<http://tibco.com>
On Sun, Nov 6, 2016 at 2:20 PM, Duncan Murdoch
<murdoch.dun...@gmail.com<mailto:murdoch.dun...@gmail.com>> wrote:
On 06/11/2016 5:02 PM, Jim Lemon wrote:
hi James,
I think you have to have a starting date ("origin") for as.Date to
convert numbers to dates.
That's true with the function in the base package, but the zoo package also has
an as.Date() function, which defaults the origin to "1970-01-01". If James is
using zoo his code would be okay. If he's not, he would have got an error, so
I think he must have been.
Duncan Murdoch
Jim
On Sun, Nov 6, 2016 at 12:10 PM, James Hirschorn
<james.hirsch...@hotmail.com<mailto:james.hirsch...@hotmail.com>> wrote:
This seemed odd so I wanted to check:
> x <- foreach(i=10000:10100, .combine='c') %do% { as.Date(i) }
yields a numeric vector for x:
> class(x)
[1] "numeric"
Should it not be a vector of Date?
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