Hi see in line
> -----Original Message----- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Christoph > Puschmann > Sent: Sunday, October 9, 2016 1:27 AM > To: Adrian Dușa <dusa.adr...@unibuc.ro> > Cc: r-help@r-project.org; Christoph Puschmann > <c.puschm...@student.unsw.edu.au> > Subject: Re: [R] Loop to check for large dataset > > Dear Adrian, > > Yes it is a cyclical data set and theoretically it should repeat this > interval until > 61327. The data set itself is divided into 2 Parts: > 1. Product category (column 10) > 2. Number of Stores Participating (column 01) Overall there are 22 different > products and in each you have 19 different stores participating. And > theoretically each store over each product category should have a 1 - 157 > week interval. Not much clearer and definitely not reproducible. From what I understand you have 22*19= 418 combinations of product/store. How do you want to put these 418 combinations into 157 rows? It seems to me that it can be somehow done with aggregate function, however without some small reproducible example we are fishing in murky water. Try to post data with let say 3 stores and 4 products to explain how your data is structured and what is or is not correct. Cheers Petr > > The part I am struggling with is how do I run a loop over the whole data set, > while checking if all stores participated 157 weeks over the different > products. > > So far I came up with this: > > n=61327 # Generate Matrix to check for values > Control = matrix( > 0, > nrow = n, > ncol = 1) > > s <- seq(from =1 , to = 157, by = 1) > CW = matrix( > s, > nrow = 157, > ncol = 1 > ) > > colnames(CW)[1] <- ’s' > > CW = as.data.frame(CW) > > for (i in 1:nrow(FD)) { # Let run trhough all the rows > for (j in 1:157) { > if(FD$WEEk[j] == C$s[j]) { > Control[i] = 1 # coresponding control row = 1 > } else { > Control[i] = 0 # corresponding control row = 0 > } > } > } > > I coded a MRE and attached an sample of my data set. > > MRE: > > #MRE > > dat <- data.frame( > Store = c(rep(8, times = 157), rep(12, times = 157)), # Number of stores > WEEK = rep(seq(from=1, to = 157, by = 1), times = 2) > ) > > > > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ________________________________ Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům. 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