Hello,

data["601",] doesn't generate an error because you can also refer to a row by its name, as an alternative to refering to it by row number. It's the same with vectors, just consider the following case.
(x <- c("601"=1, b=2))
x[1]
x["601"]  # the same

But when you want to remove it you must negate an index number so x[-"601"] is wrong for reasons already explained.
Rui Barradas


Citando Pauline Laïlle <pauline.lai...@gmail.com>:

Hi, thanks for the answer.
In this case, the row named "601" is not the 601st row of the table, but
the 117th. data[601,] actually refers to a non existing row.
I was wondering why data[-"601,] generates an error message whereas
data["601",] does not?

2016-09-20 19:08 GMT+02:00 Bert Gunter <bgunter.4...@gmail.com>:

Hint: "601"  is not 601.

Have you gone through any R tutorials?

Cheers,
Bert
Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Tue, Sep 20, 2016 at 5:42 AM, Pauline Laïlle
<pauline.lai...@gmail.com> wrote:
> Dear all,
>
> I built a dataframe with read.csv2(). Initially, row names are integers
> (order of answers to a survey). They are listed in the csv's first
column.
> The import works well and my dataframe looks like I wanted it to look.
>
> Row names go as follows :
>  [1] "6"   "29"  "31"  "32"  "52"  "55"  "63"  "71"  "72"  "80"  "88"
"89"
>  "91"  "93"  "105" "110" "111" "117" "119" "120"
>  [21] "122" "127" "128" "133" "137" "140" "163" "165" "167" "169" "177"
> "178" "179" "184" "186" "192" "193" "200" "201" "228"
> etc.
>
> I would like to drop rows "601" & "604" to clean the dataframe.
>
> While data["601",] shows me the first row i'd like to drop, data[-"601",]
> returns the following :
> Error in -"601" : invalid argument to unary operator
>
> idem with data[c("601","604"),] and data[-c("601","604"),]
>
> It is the first time that I run into this specific error. After reading a
> bit about it I still don't understand what it means and how to fix it.
>
> Thanks for reading!
> Best,
> Pauline.
>
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>
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