Hello,
What about the following?
ff <- dimInfo[grep('HS', dimInfo)]
sub("^.*HS_([[:alnum:]]).*$", "\\1", ff)
Hope this helps,
Rui Barradas
Citando Doran, Harold <hdo...@air.org>:
I have produced a terribly inefficient piece of codes. In the end,
it gives exactly what I need, but clumsily steps through multiple
steps which I'm sure could be more efficiently reduced.
Below is a reproducible example. What I have to begin with is
character vector, dimInfo. What I want to do is parse this vector 1)
find the elements containing 'HS' and 2) grab *only* the first
character after the "HS_". The final line of code in the example
gives what I need.
Any suggestions on a better approach?
Harold
dimInfo <- c("RecordID", "oppID", "position", "key", "operational",
"IsSelected",
"score", "item_1_HS_conv_ovrl_scr", "item_1_HS_elab_ovrl_scr",
"item_1_HS_org_ovrl_scr")
ff <- dimInfo[grep('HS', dimInfo)]
gg <- strsplit(ff, 'HS_')
hh <- sapply(1:3, function(i) gg[[i]][2])
substr(hh, 1, 1)
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.