On Sat, Sep 10, 2016 at 07:23:37PM +0000, Glenn Schultz wrote: > ... > Below is the function that I am writing. I am using sed to replace the hex > characters. First, to get past NUL I use sed to replace hex 00 with hex 20. > This has worked. Once the Nul is removed and can successfully parse the file > with ReadLine sub_str. This final step before delimiting the file and making > it nice and tidy is to remove the hex 20 characters. I am using the same > strategy to eliminate the spaces and sed command works in a shell but does > not work in the R function. What am I doing wrong? I have dput - some of > the nastier lines with hex 20 characters below my code.
I believe that you will find that the sed "d" command deletes the
"pattern space" (in a simple text file, it would delete the line) in
which the specified regular expression is found.
I suspect that you actually want to eliminate the "space" characters
themselves, so rather than:
> ...
> # The file has been parsed accroding to length 400 for each data element.
> # The next step is to remove all the trailing white space hex character
> # x20
>
> sedcommand2 <- paste("sed -e '/\\x20/d' <",
what is wanted is:
sedcommand2 <- paste("sed -e 's/\\x20//g' <",
> ...
Note that you might consider using R's gsub() function to perform that
"space elimination"both natively and a bit earlier.
Peace,
david
--
David H. Wolfskill r...@catwhisker.org
Those who would murder in the name of God or prophet are blasphemous cowards.
See http://www.catwhisker.org/~david/publickey.gpg for my public key.
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