Hello,
Try placing the & immediately after the substr() conditions, like this:
base <- baseR[substr(baseR[['ID']],3,4)!='03' &
substr(baseR[['ID']],11,12)!='01' &
substr(baseR[['ID']],11,12)!='11',]
Maybe I'm wrong but R might have decided that the instructions were
complete before the next lines were reached.
And your attachment didn't make through. Use dput to post a data example.
dput(head(baseR, 30)) #paste the output of this in a mail
Hope this helps,
Rui Barradas
Citando Rosa Oliveira <rosit...@gmail.com>:
Dear all,
I have searched all over and didn´t found an answer :( Sorry, I'm new.
I need urgently to "not analyse"the weight the ID's that have 07 in the
position 3 and 4 respectively, 01 or 11 in positions 11 and 12 of ID
variable. .
I used the following code:
base<--baseR[substr(baseR$'ID',3,4)!='03'
&substr(baseR$'ID',11,12)!='01'
&substr(baseR$'ID',11,12)!='11',]
But, instead of removing just the id's that respect the 3 conditions
simultaneously, base don't have all the id's that have 03 in the 3 and 4
positions os id variable, neither 01 in positions 11 and 12 of ID,
neither 11
in positions 11 and 12 of ID variable.variable.
So, it seems, that the code exclude all the conditions, as it was a OR (|)
condition in spite of AND (&) condition.
Can anyone help me please?
I attach the data.
Best,
Rosa Oliveira
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