> On Jul 27, 2016, at 5:03 AM, Ismail SEZEN <sezenism...@gmail.com> wrote: > > >>> The time column is factor. I want to convert each time to the following >>> format: >>> >>> 20111211003000 >>> >>> 20111211013000 >>> >>> 20111211020000 >>> >>> (Year)(month)(date)(hr)(min)(sec) >> >>> newTimeDt <- strptime(Time, format="%d%b%y:%H:%M") >>> newTimeDt >> [1] "2011-12-27 00:30:00 PST" "2011-12-27 01:30:00 PST" "2011-12-27 02:00:00 >> PST" >>> newTimeDt <- as.POSIXct(Time, format="%d%b%y:%H:%M") >>> newTimeDt >> [1] "2011-12-27 00:30:00 PST" "2011-12-27 01:30:00 PST" "2011-12-27 02:00:00 >> PST" >>> newOut <- format(newTimeDt, "%Y%m%d%H%M") >>> newOut >> [1] "201112270030" "201112270130" "201112270200" >>> newOut <- format(newTimeDt, "%Y%m%d%H%M%S") >>> newOut >> [1] "20111227003000" "20111227013000" "20111227020000" > > Addition to David, if you use functions similar to read.csv or read.table to > read dates from a file, you have to set >
I am not opposed to using stringsAsFactors=FALSE at the time of data input, but since there is an as.POSIXct.factor function it was not needed here. > stringsAsFactors = T Wrong: It would need to be FALSE to be anything other than the default. And you would not be reading Dates but rather character values. > > in function parameters or set data.frame column as character seperately. I did test my code on a factor vector. -- David Winsemius Alameda, CA, USA ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
