Thanks for the suggestion Berend. I just tried with numeric(n) and its
working for x and y.
But my issue is different and its not resolved yet.
-Vineetha
On Thu, Jun 16, 2016 at 1:19 PM, Berend Hasselman <b...@xs4all.nl> wrote:
>
> > On 16 Jun 2016, at 21:04, Eduardo M. A. M.Mendes <emammen...@gmail.com>
> wrote:
> >
> >
> >> On Jun 16, 2016, at 3:50 PM, Berend Hasselman <b...@xs4all.nl> wrote:
> >>
> >>
> >>> On 16 Jun 2016, at 20:02, Eduardo M. A. M.Mendes <emammen...@gmail.com>
> wrote:
> >>>
> >>> Thanks Bill for pointing this out. I haven’t noticed it.
> >>>
> >>> Vineetha, try as.double(rep(0,n)) or as.matrix(rep(0,n)),
> >>>
> >>
> >> Why not simply numeric(n)?
> >>
> >> Berend Hasselman
> >>
> >
> > as.numeric(rep(0,n)) works too. Please remember that he wants a vector
> nor a scalar.
> >
>
> Indeed it does. And I certainly remembered that the OP wants a vector of
> length n.
> But so does numeric(n), which creates a length n vector. Just try
> numeric(2).
>
> Berend
>
>
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