Hello,
Sorry, forget my first answer, I misunderstood what you wanted.
Let's try again.
First of all you have a typo in your second sample2, you wrote 'sample
2' with a space.
Now try this.
fun2 <- function(n){
merge(lst[[n]], lst[[n + 1]])
}
N <- which(seq_along(lst) %% 2 == 1)
lst2 <- lapply(N, fun2)
result <- do.call(rbind, lst2)
result
Hope this helps,
Rui Barradas
Citando Ed Siefker <ebs15...@gmail.com>:
> I have a list of data as follows.
>> list(data.frame(name="sample1", red=20), data.frame(name="sample1",
>> green=15), data.frame(name="sample2", red=10),
>> data.frame(name="sample 2", green=30))
>
> [[1]]
> name red
> 1 sample1 20
>
> [[2]]
> name green
> 1 sample1 15
>
> [[3]]
> name red
> 1 sample2 10
>
> [[4]]
> name green
> 1 sample2 30
>
> I would like to massage this into a data frame like this:
>
> name red green
> 1 sample1 20 15
> 2 sample2 10 30
>
> I'm imagining I can use aggregate(mylist, by=samplenames, merge)
> right? But how do I get the list of samplenames? How do I subset
> each dataframe inside the list?
>
> ______________________________________________
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> http://www.R-project.org/posting-guide.htmland provide commented,
> minimal, self-contained, reproducible code.
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