Actually not sure my previous answer does what you wanted. Using your
approach:
t2pd=subset(df,grepl("t2",df$Command) & grepl("pd",df$Command))
Should work.
I think the regex pattern you are looking for is:
Subset(df,grepl("(.* t2.*pd.* )|(.* pd.* t2.*)",df$Command)
On Sat, Apr 30, 2016, 7:07 PM Tom Wright <t...@maladmin.com> wrote:
> subset(df,grepl("t2|pd",x$Command))
>
>
> On Sat, Apr 30, 2016 at 2:38 PM, ch.elahe via R-help <r-help@r-project.org
> > wrote:
>
>> Hi all,
>>
>> I have one factor variable in my df and I want to extract the names from
>> it which contain both "t2" and "pd":
>>
>> 'data.frame': 36919 obs. of 162 variables
>> $TE :int 38,41,11,52,48,75,.....
>> $TR :int 100,210,548,546,.....
>> $Command :factor W/2229 levels
>> "_localize_PD","_localize_tre_t2","_abdomen_t1_seq","knee_pd_t1_localize","pd_local_abdomen_t2"...
>>
>> I have tried this but I did not get result:
>>
>> t2pd=subset(df,grepl("t2",Command) & grepl("pd",Command))
>>
>>
>> does anyone know how to apply AND in grepl?
>>
>> Thanks
>> Elahe
>>
>> ______________________________________________
>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
