Denis Chabot wrote:
> Hi,
>
> Simple question, but I did not figure out how to find the answer on my
> own (wrong choice of keywords on my part).
>
> I have a character variable for time of day that has entries looking
> like "6h30", "7h40", "12h25", "23h", etc. For the sake of this
> message, say
>
> h = c("3h30", "6h30", "9h40", "11h25", "14h00",
> "15h55", "23h")
>
> I could not figure out how to use chron to import this into times, so
> I tried to extract the hours and minutes on my own.
>
> I used strsplit and got a list:
>
> h2 = strsplit(h, "h")
> > h2
> [[1]]
> [1] "3" "30"
>
> [[2]]
> [1] "6" "30"
>
> [[3]]
> [1] "9" "40"
>
> [[4]]
> [1] "11" "25"
>
> [[5]]
> [1] "14" "00"
>
> [[6]]
> [1] "15" "55"
>
> [[7]]
> [1] "23"
>
> It is where I am stuck. I would have like to extract a vector of
> "hours" from this list, and a vector of "minutes", to reconstruct a
> time of day.
>
> But the only command I know, unlist, makes a long vector of h, min, h,
> min, h, min.
>
> For this in particular, but lists in general, how can one extract the
> first item of each element in the list, then the second item of each
> element, etc.?
>
you can also want to convert this representation to something cron-readable:
times(gsub("([0-9]+)h([0-9]*)", "\\1:0\\2:0", h))
[1] 03:30:00 06:30:00 etc.
(the first 0 in the replacement accommodates for missing minutes digits,
the second for seconds)
vQ
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
