This looks very much like a homework problem and this list has a "no homework" policy.
cheers, Rolf Turner -- Technical Editor ANZJS Department of Statistics University of Auckland Phone: +64-9-373-7599 ext. 88276 On 04/02/16 17:08, smart hendsome via R-help wrote:
Hi everyone, I have problem regarding to generate arrival of time based on uniform random number. Let day0 = 0.383, lambda = 0.2612 1) Generate uniform random number (already settled) using the code below: set.seed(1234) rand.no <- function(n,itr){ matrix(runif(n*itr, 0, 1), nrow=n, ncol=itr) } x<-rand.no(10,1) 2) For day 1, a) if 1st rand.no < day0, then its not rain, else its rain (i want the rseult in next colum, let say rain) 3) For day 2 and so on ( it depend from next rain when it happened) 4) Next rain, to know the next rain i need i need to calculate using the exponential a) 1st rain = - ln (1st rand.no) / lambda b) 2nd nextRain = 1st rain - ln (2nd rand.no) / lambda c) 3rd nextRain = 2nd next rain - ln (3rd rand.no)/lambda, and so on eg: if nextRain = 2.435, then 2nd day will rain Hope anyone can help me solve this problems. Thanks so much.
______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.