This looks very much like a homework problem and this list has a "no
homework" policy.
cheers,
Rolf Turner
--
Technical Editor ANZJS
Department of Statistics
University of Auckland
Phone: +64-9-373-7599 ext. 88276
On 04/02/16 17:08, smart hendsome via R-help wrote:
Hi everyone,
I have problem regarding to generate arrival of time based on uniform random
number.
Let day0 = 0.383, lambda = 0.2612
1) Generate uniform random number (already settled) using the code below:
set.seed(1234)
rand.no <- function(n,itr){
matrix(runif(n*itr, 0, 1), nrow=n, ncol=itr)
}
x<-rand.no(10,1)
2) For day 1,
a) if 1st rand.no < day0, then its not rain, else its rain (i want the
rseult in next colum, let say rain)
3) For day 2 and so on ( it depend from next rain when it happened)
4) Next rain,
to know the next rain i need i need to calculate using the exponential
a) 1st rain = - ln (1st rand.no) / lambda
b) 2nd nextRain = 1st rain - ln (2nd rand.no) / lambda
c) 3rd nextRain = 2nd next rain - ln (3rd rand.no)/lambda, and so on
eg: if nextRain = 2.435, then 2nd day will rain
Hope anyone can help me solve this problems. Thanks so much.
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