It seems your autocorrect is playing tricks on you but if I understand you correctly you have a two digit year and want to convert that to a four digit year? That's not uniquely possible of course; by convention, as the documentation to strptime() says:
On input, values 00 to 68 are prefixed by 20 and 69 to 99 by 19 – that is the behaviour specified by the 2004 and 2008 POSIX standards... If this is correct for you, you need to convert the string to a time object and the time object back to string. The format specifier %Y prints four-digit years: d <- "7/27/59" strptime(d, format="%m/%d/%y") # "2059-07-27 EDT" x <- strptime(d, format="%m/%d/%y") strftime(x, format="%m/%d/%Y") # "07/27/1977" B. On Feb 3, 2016, at 11:03 AM, carol white via R-help <r-help@r-project.org> wrote: > Hi,might be trivial but how to determine the year of a date which is in the > %m/%d/%y format and those whose year is century should be modified to ISO so > that all date will have with year in ISO? > Regards, > Carol > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
