It seems your autocorrect is playing tricks on you but if I understand you 
correctly you have a two digit year and want to convert that to a four digit 
year? That's not uniquely possible of course; by convention, as the 
documentation to strptime() says:

  On input, values 00 to 68 are prefixed by 20 and 69 to 99 by 19 – that
  is the behaviour specified by the 2004 and 2008 POSIX standards...

If this is correct for you, you need to convert the string to a time object and 
the time object back to string. The format specifier %Y prints four-digit years:


d <- "7/27/59"
strptime(d, format="%m/%d/%y")   # "2059-07-27 EDT"
x <- strptime(d, format="%m/%d/%y")

strftime(x, format="%m/%d/%Y")   # "07/27/1977"



B.







On Feb 3, 2016, at 11:03 AM, carol white via R-help <r-help@r-project.org> 
wrote:

> Hi,might be trivial but how to determine the year of a date which is in the 
> %m/%d/%y format and those whose year is century should be modified to ISO so 
> that all date will have with year in ISO?
> Regards,
> Carol
> 
>       [[alternative HTML version deleted]]
> 
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