Dear Bob, You want...
> qf( .95,1, 1) [1] 161.4476 Best, Fraser -----Original Message----- From: Robert Sherry [mailto:rsher...@comcast.net] Sent: Monday, December 21, 2015 2:51 PM To: R Project Help Subject: [R] F Distribution When I use a table, from a Schaum book, I see that for the 95 percentile, with v_1 = 1 and v_2 = 1 the value is 161. In the modern era, looking values up in a table is less than ideal. Therefore, I would expect R to have a function to do this and based upon my reading of the documentation, I would expect the following call to get the value I expect: pf( .95,1, 1) However, it produces 0.4918373 Therefore, I conclude that I am using the wrong function. What function should I use? Thanks Bob ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
