I as not able to make sense of your post. Maybe others can. However,
you have posted here several times, now. You should therefore know
that providing a reproducible example (providing data by e.g. dput() )
**and showing exactly what output you want** would improve your chance
of a helpful response.
'Nuff said.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Dec 15, 2015 at 7:56 AM, debra ragland via R-help
<r-help@r-project.org> wrote:
> Hello,
>
> I have tried this 2 ways and I keep coming to a dead end as I am not very
> proficient in R.
>
> I have a logical matrix, where I would like to generate every row-wise pair
> of logical values for further testing. That is row1, row2; row 1, row3 etc.
> Ideally, I would like to assign a pre-generated vector of values to each pair
> such that each combination of rows may be split into 2 groups with each
> variable appearing only once.
>
> This is similar to the WRONG way I've been trying to do this;
>
> vector = runif(4, 1.0, 2.0)
> logmat<-matrix(c(rep(c(F,T,F),3), rep(c(T,F,T),3), rep(c(T,T,F),3),
> rep(c(F,F,T),3)), ncol=4)
> logmat1 = logmat[1:2,]
> dbv=rep(vector, 2)
> split(dbv,logmat1)
>
>
> As you can see there's no proper distinction between what should be
> absolutely assigned to "TRUE" and what should be assigned to "FALSE". --Note
> my actual data is named.
>
> To try and correct this mistake on a subset of my data I've been trying to
> use what I'll call "method 1" where
>
> a = c(TRUE, TRUE, TRUE, FALSE, FALSE, TRUE)
> names(a)=c(a,b,c,d,e,f)
>
> b = c(TRUE, TRUE, FALSE, FALSE, TRUE, FALSE)
> names(b)=c("a","b","c","d","e","f")
>
> Using this function, I am able to separate which variables are exactly "TRUE"
> or "FALSE
>
> logical_groups = function (a, b) {
> r = list()
> s = a + b
> r$'TRUE' = names(subset(s, s == 2))
> r$'FALSE' = names(subset(s, s == 0))
> r$'OR' = names(subset(s, s==1))
> return(r)
> }
>
>> logical_groups(a,b)
> $`TRUE`
> [1] "a" "b"
>
> $`FALSE`
> [1] "d"
>
> $OR
> [1] "c" "e" "f"
>
>
> The return, as you can see is a list.
> I have a vector of values that match the names a-f in a and b above, i.e.
> vector=runif(6, 1.0, 2.0)
> names(vector) = c("a","b","c","d","e","f")
>
> and I would like to add these values to the corresponding (names in the) list
> so that I may run the wilcox.test correctly using the 'TRUE' and 'FALSE
> elements. But I am not sure how to achieve this.
>
> I have also tried "method 2"-- starting with;
> t=rbind(a, b, vector) to give;
>>t
> a b c d e f
> a 1.000000 1.000000 1.000000 0.00000 0.000000 1.000000
> b 1.000000 1.000000 0.000000 0.00000 1.000000 0.000000
> vector 1.012097 1.431088 1.832276 1.12801 1.780018 1.682804
>
> where I then try
> t2 =t[1,]+t[2,]
> t3=rbind(t2, t[3,]) to give;
>> t3
> a b c d e f
> t2 2.000000 2.000000 1.000000 0.00000 1.000000 1.000000
> 1.012097 1.431088 1.832276 1.12801 1.780018 1.682804
>
> But again, I am not sure how to split the t3 matrix where the first row == 2
> or == 0.
>
> I have been searching but I think I'm just confusing myself. I am very late
> in my pregnancy and my brain just won't function fully.
>
> I hope this makes sense. Any help is appreciated.
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
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