Hi Ragia,
Perhaps the easiest way is to split the data frame into a list by the
values of v1:
sdf<-split(df,df$v1)
Then rename the elements of sdf for convenience:
names(sdf)<-paste("v1",1:5,sep="_")
Now you can extract whatever you like"
sdf$v1_1$v2
[1] 3 4 8
Of course if you only want the values of v2:
split(df$v2,df$v1)
$`1`
[1] 3 4 8
$`2`
[1] 9 10 6
$`3`
[1] 4 5 8
$`4`
[1] 9 6 8
$`5`
[1] 4 5 6
Jim
On Sun, Dec 6, 2015 at 8:55 PM, Ragia Ibrahim <ragi...@hotmail.com> wrote:
> Dear group,
>
> I have the following data frame
>
> v1 v2 v3 v4 v5
> 1 1 3 1 3.5 1
> 2 1 4 3 3.5 1
> 3 1 8 3 3.5 1
> 4 2 9 8 2.5 1
> 5 2 10 9 2.5 1
> 6 2 6 3 1.5 1
> 7 3 4 3 2.0 1
> 8 3 5 3 1.0 1
> 9 3 8 3 1.0 1
> 10 4 9 8 2.0 1
> 11 4 6 5 1.0 1
> 12 4 8 4 1.0 1
> 13 5 4 3 2.0 1
> 14 5 5 3 2.0 1
> 15 5 6 5 2.0 1
>
> I'm trying to split it into data frames where each equal v1 so all v1==1
> in data frame and all v1==2 in separate data frame and so on.
> so it would be
>
> v1 v2 v3 v4 v5
> 1 1 3 1 3.5 1
> 2 1 4 3 3.5 1
> 3 1 8 3 3.5 1
> then
> v1 v2 v3 v4 v5
> 4 2 9 8 2.5 1
> 5 2 10 9 2.5 1
> 6 2 6 3 1.5 1
> .......
> ...
> and so on
>
> I tried
> a<- split(df, df$v1==1)
> but the resulting class is a list and when I try to access for example
> a$v2 it gave me NULL ??
>
> how can I split it an get each vector of v2 for each group,
> lots of thanks
> Ragia
> ______________________________________________
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