Or sorry, I should clarify, I struggle with putting components together when it
comes to looping.
On Thursday, December 3, 2015 11:43 AM, debra ragland <ragland.de...@yahoo.com>
wrote:
Thanks again!
And no Bert, this is not homework. I have a very minimal background in R and
struggle with putting concepts together.
But thanks anyway.
On Thursday, December 3, 2015 11:04 AM, Boris Steipe <boris.ste...@utoronto.ca>
wrote:
Use your logical vector to extract the x, y values for the test from the rows
of the matrix:
x <- mat[3, x2]
y <- mat[3, !x2]
Or: use the formula version of wilcox.test as explained in ?wilcox.test
B.
On Dec 3, 2015, at 10:28 AM, debra ragland via R-help <r-help@r-project.org>
wrote:
> I have read in a sequence alignment and have done the necessary steps to
> separate and store the elements of the original input into a new list of
> character vectors. I have compared the sequence list to a "standard" vector,
> such that the return is a matrix of logical values indicating TRUE if there
> is a match to the standard and FALSE where there is no match.
>
> An example;
>
> mylist=c("AAEBCC", "AABDCC", "AABBCD")
> list.2 <- strsplit(mylist, split=NULL)
> # setting a standard for comparison
> std.string <- "AABBCC"
> standard <- unlist(strsplit(std.string, split=NULL))
> #create a logical matrix
> mat<-sapply(list.2, function(x) x==standard)
>> mat
>
>
> [,1] [,2] [,3]
> [1,] TRUE TRUE TRUE
> [2,] TRUE TRUE TRUE
> [3,] FALSE TRUE TRUE
> [4,] TRUE FALSE TRUE
> [5,] TRUE TRUE TRUE
> [6,] TRUE TRUE FALSE
>
> Where the number of columns is the same length as the original input strings
> I compared (15) and the number of rows corresponds is the same as the number
> of strings from the input (99).
>
> I also have a named numeric vector(of length 15)--where the "names" of the
> the values match those of the columns of the logical matrix. For the example
>
> x2 = runif(3, 5.0, 7.5)
> names(x2) = 1:3
>> x2
> 1 2 3
> 5.352611 7.058169 6.993105
>
> For each row in the in the logical matrix I want to combine the logical
> values with the values from the numeric vector so that I can run a
> wilcox.test using those values that are "TRUE" against those that are "FALSE".
>
> For instance if each row&vector pairing was a mini data.frame it would look
> like
>
> df=data.frame(x2, mat[3,])
>> df
> 1 5.352611 FALSE
> 2 7.058169 TRUE
> 3 6.993105 TRUE
> wilcox.test(df) #based on all true values vs. all false values
>
> How can this be achieved?
>
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