Good day, Yes, exactly. I found that aggregate is another alternative which doesn't require a package dependency, although the column formatting is less suitable, always prepending x.
aggregate(warpbreaks[, 1], warpbreaks[, 2:3], function(breaks) c(Min = min(breaks), Med = median(breaks), Max = max(breaks))) wool tension x.Min x.Med x.Max 1 A L 25 51 70 2 B L 14 29 44 3 A M 12 21 36 4 B M 16 28 42 5 A H 10 24 43 6 B H 13 17 28 -------------------------------------- Dario Strbenac PhD Student University of Sydney Camperdown NSW 2050 Australia ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
