Wow! So many (simpler) ways to skin a cat. Thanks! On Fri, Jul 24, 2015 at 8:07 PM, David Winsemius <dwinsem...@comcast.net> wrote:
> > On Jul 24, 2015, at 4:37 PM, Janh Anni wrote: > > > Hello Jeff, > > > > Thanks a lot. I tried it and see that it prints out the entire 100 > partial > > sums, so I can take the last value as the partial sum for the first 100 > > terms. Would there be any way cumsum can print only the nth partial sum, > > i.e. the last value in the array, instead of printing the entire array? > > Thanks again. > > Wouldn't that just mean using sum instead of cumsum????? > > Can even check the error from the analytical limit. > > > sum(1/(1:100)^2) - pi^2/6 > [1] -0.009950167 > > > > > > Joseph > > > > On Fri, Jul 24, 2015 at 2:02 PM, Jeff Newmiller < > jdnew...@dcn.davis.ca.us> > > wrote: > > > >> Please reply-all so the mailing list stays in the loop. > >> > >> cumsum(1/(1:100)^2) > >> > >> gives you the partial sums up through i=100. > >> > --------------------------------------------------------------------------- > >> Jeff Newmiller The ..... ..... Go > Live... > >> DCN:<jdnew...@dcn.davis.ca.us> Basics: ##.#. ##.#. Live > >> Go... > >> Live: OO#.. Dead: OO#.. Playing > >> Research Engineer (Solar/Batteries O.O#. #.O#. with > >> /Software/Embedded Controllers) .OO#. .OO#. > rocks...1k > >> > --------------------------------------------------------------------------- > >> Sent from my phone. Please excuse my brevity. > >> > >> On July 24, 2015 10:30:09 AM PDT, Janh Anni <annij...@gmail.com> wrote: > >>> Hello Jeff, > >>> > >>> Thank you so much for the suggestion, I searched cumsum as suggested > >>> but > >>> not sure it is what I had in mind. For instance if I had the infinite > >>> series: [image: Inline image 1] > >>> > >>> and want to compute the sum of the, say, first 100 terms, how could I > >>> use > >>> cusum to do that? > >>> > >>> Thanks again, > >>> > >>> Janh > >>> > >>> > >>> On Thu, Jul 23, 2015 at 11:51 PM, Jeff Newmiller > >>> <jdnew...@dcn.davis.ca.us> > >>> wrote: > >>> > >>>> ?cumsum > >>>> > >> > >>> > --------------------------------------------------------------------------- > >>>> Jeff Newmiller The ..... ..... Go > >>> Live... > >>>> DCN:<jdnew...@dcn.davis.ca.us> Basics: ##.#. ##.#. Live > >>>> Go... > >>>> Live: OO#.. Dead: OO#.. > >>> Playing > >>>> Research Engineer (Solar/Batteries O.O#. #.O#. with > >>>> /Software/Embedded Controllers) .OO#. .OO#. > >>> rocks...1k > >>>> > >> > >>> > --------------------------------------------------------------------------- > >>>> Sent from my phone. Please excuse my brevity. > >>>> > >>>> On July 23, 2015 8:23:39 PM PDT, Janh Anni <annij...@gmail.com> > >>> wrote: > >>>>> Dear All, > >>>>> > >>>>> Does anyone know of any R functions that compute partial sums of > >>>>> series? > >>>>> > >>>>> Thanks in advance! > >>>>> > >>>>> Janh > >>>>> > >>>>> [[alternative HTML version deleted]] > >>>>> > >>>>> ______________________________________________ > >>>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > >>>>> https://stat.ethz.ch/mailman/listinfo/r-help > >>>>> PLEASE do read the posting guide > >>>>> http://www.R-project.org/posting-guide.html > >>>>> and provide commented, minimal, self-contained, reproducible code. > >>>> > >>>> > >> > >> > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > David Winsemius > Alameda, CA, USA > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
