R-help readers, For your information ...
The package stringi is required to run Alex's code. Alex's message was cross posted to StackOverflow, and seems to have been answered there, http://stackoverflow.com/questions/31398466/r-stri-locate-all-creating-a-start-and-end-matrix Jean On Tue, Jul 14, 2015 at 12:33 AM, Alex Kim via R-help <r-help@r-project.org> wrote: > Hello, > > I am trying to create a matrix that looks like this, using the > stri_locate_all function. > > > x <- "ABCDJAKSLABCDAKJSABCD" > > m <- stri_locate_all_regex(x, 'ABCD') > > m > [[1]] > start end > [1,] 1 4 > [2,] 10 13 > [3,] 18 21 > > I tried converting m into a matrix, however it always seems to wrap around > the wrong way: > > > output <- matrix(unlist(m), ncol = 2, byrow = TRUE) > > output > [,1] [,2] > [1,] 1 10 > [2,] 18 4 > [3,] 13 21 > > I want to output the start locations in the first column and the end > locations in the second column into a matrix to look like this. > > [,1] [,2] > [1,] 1 4 > [2,] 10 13 > [3,] 18 21 > > Thank you for your help, > Alex > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
