Hello, I am still in the process of familiarizing myself with R, pardon me if this is basic. I want to run a leave one out procedure for a 40 member dataset. At the moment I am doing it via a simple for loop. I wanted to know if there is a superior way to do it. I read about the loocv command here - http://artax.karlin.mff.cuni.cz/r-help/library/DMwR/html/loocv.html. Since I need to save the output generated in each iteration, I am not very sure how exactly to implement the same using the loocv command. If you could give me an insight into how to do it/ suggest quicker ways to do leave one out cross validation, it would be really helpful!
Thanks, Vyshnnavi [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.