On Jun 11, 2015, at 12:25 PM, Kevin Kowitski wrote:
> Hey,
>
> I am having an issue with a for loop that is intended to read index values
> by row and column so that it can pull out the valuable information. My issue
> is that I am using a data.frame(which(df==1, arr.ind=TRUE))
That would be coercing a matrix to a dataframe. But why?
> to find the index of the values in my data frame that are equal to 1. This
> outputs a data frame of 71 rows which is confirmed by the "nrows" function.
> However, when I try to break up the rows and columns using the code below I
> am producing two vectors of 75 values, even though there are only 71 and the
> for loop is from 1 to the value of 71. Am I making this task more
> complicated than it needs to be?
>
> if(countRaw > 0){
How the value of countRow enters into this is entirely unclear.
> index_R_df<-rbind( index_R_df,
> data.frame(which(sapply(data2[0:24,],
R does NOT use zero-based indexing.
> match, INDString, nomatch=0)==1, arr.ind=TRUE)))
You need to explain what you are doing here. It's a bit too obscure to me how
we should know that index_R_df will line up with the items would drop out of:
data.frame(which(sapply(data2[0:24,],match, INDString, nomatch=0)==1,
arr.ind=TRUE)))
I would have expected some `name` to be followed by `[` then `which(...)`
> index_lengthR<-nrow(index_R_df)
>
> for (j in 1:index_lengthR){
> index_rowsR<-c(index_rowsR,
> index_R_df[j,1])
> index_colsR<-c(index_colsR,
> index_R_df[j,2])
> #rowsPass_R<-c(unique(index_rowsR))
> #collect_rows<-c(collect_rows,
> rowsPass_R)
> }
>
There are too many missing here for me to do anything useful. You are either
only giving us a fragment of code and using zero based indexing. Without a
data example, I'm throwing it back to you ot someone in the readership with
better intuition or imagination than I possess.
> I'm sorry if this seems very novice, I'm new to R.
>
> -Kevin
> ______________________________________________
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David Winsemius
Alameda, CA, USA
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