Maybe what you really want is the ?stack function. --------------------------------------------------------------------------- Jeff Newmiller The ..... ..... Go Live... DCN:<jdnew...@dcn.davis.ca.us> Basics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/Batteries O.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --------------------------------------------------------------------------- Sent from my phone. Please excuse my brevity.
On April 16, 2015 4:59:47 AM PDT, Joachim Audenaert <joachim.audena...@pcsierteelt.be> wrote: >Thanks, > >indeed norm should be in the same group as as the months. everything >works >fine when the number of data is quite small, but with big datasets (15 >000 >values) things seem to go wrong and I can't explain why. It puts norm >as >an individual column in stead of in the group of months as it does when > >the dataset is small. > >Met vriendelijke groeten - With kind regards, > >Joachim Audenaert >onderzoeker gewasbescherming - crop protection researcher > >PCS | proefcentrum voor sierteelt - ornamental plant research > >Schaessestraat 18, 9070 Destelbergen, Belgi� >T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95 >E: joachim.audena...@pcsierteelt.be | W: www.pcsierteelt.be > > > >From: PIKAL Petr <petr.pi...@precheza.cz> >To: Joachim Audenaert <joachim.audena...@pcsierteelt.be> >Cc: "r-help@r-project.org" <r-help@r-project.org> >Date: 16/04/2015 13:41 >Subject: RE: [R] melt function chooses wrong id variable with >large datasets > > > >Hi > >With this dataset I get > >> dd.m0<-melt(dataset, na.rm=T) >Using norm as id variables >> head(dd.m0) > norm variable value >1 45.8713463281901 januari 38.1 >2 24.047250681782984 januari 32.4 >3 3.7533684144746324 januari 34.5 >4 38.594241119279324 januari 20.7 >5 26.391897460120358 januari 21.5 >6 61.746470001194638 januari 23.1 >> >or > >dd.m<-melt(dataset, id.vars=NULL, na.rm=T) > >> head(dd.m) > variable value >1 januari 38.1 >2 januari 32.4 >3 januari 34.5 >4 januari 20.7 >5 januari 21.5 >6 januari 23.1 >> tail(dd.m) > variable value >255 norm 4.856812959269508 >256 norm 5.3982910143166514 >257 norm 46.553976273304215 >258 norm 17.566272518985429 >259 norm 20.552451905814117 >260 norm 61.894775704479279 > >The latter will put norm to the same column as months. Is it intended? > >Maybe you want > >> dd.m1<-melt(dataset[,-13], na.rm=T) >No id variables; using all as measure variables >> head(dd.m1) > variable value >1 januari 38.1 >2 januari 32.4 >3 januari 34.5 >4 januari 20.7 >5 januari 21.5 >6 januari 23.1 >> tail(dd.m1) > variable value >235 december 20.7 >236 december 30.9 >237 december 36.2 >238 december 21.0 >239 december 20.2 >240 december 21.3 > >Cheers >Petr > >From: Joachim Audenaert [mailto:joachim.audena...@pcsierteelt.be] >Sent: Thursday, April 16, 2015 1:13 PM >To: PIKAL Petr >Cc: r-help@r-project.org >Subject: RE: [R] melt function chooses wrong id variable with large >datasets > >Hello, > >This is a part of my dataset: > >structure(list(januari = c(38.1, 32.4, 34.5, 20.7, 21.5, 23.1, >29.7, 36.6, 36.1, 20.6, 20.4, 30.1, 38.7, 41.4, 37, 36, 37, 38, >23, 26.7), februari = c(31.5, 36.2, 38.2, 26.4, 20.9, 21.5, 30.2, >33.4, 32.6, 22.2, 21.7, 30, 35.7, 32.8, 39.3, 25.5, 23, 19.9, >21.3, 20.8), maart = c(34.2, 27, 24.2, 19.9, 19.7, 21.5, 30.6, >30, 19, 19.6, 20.6, 23.6, 17.9, 17.3, 21.4, 24.1, 20.9, 30.1, >32.6, 21.3), april = c(26.3, 29.6, 30.3, 23.6, 28.4, 20.7, 24.1, >27.3, 23.2, 18.3, 24.6, 27.4, 20.4, 18.1, 25.2, 19.8, 21, 23.7, >19.6, 18.1), mei = c(23.7, 24, 17.2, 23.2, 25.2, 17.2, 16, 15.6, >13.4, 16, 16.8, 14.6, 19.4, 21, 19.5, 18.5, 13.3, 13.7, 14.3, >14.1), juni = c(17.7, 14.2, 16.6, 15.7, 13.7, 14.7, 13.1, 12.9, >15.4, 11.9, 15.2, 15.3, 16.5, 16.1, 11.7, 11.2, 11.5, 10.8, 16.1, >14.8), juli = c(15.7, 14.5, 10.8, 10.5, 13.4, 12.2, 13.2, 13, >12.4, 13.1, 9.8, 10.5, 13.4, 11, 13.1, 15, 16.7, 16.1, 18.2, >15.7), augustus = c(12.9, 12.8, 15.2, 14.5, 17.2, 14.5, 14.4, >11, 13.1, 13.6, 14.6, 12.7, 13.6, 12.7, 15.5, 17.4, 15.2, 14.2, >17.7, 19.2), september = c(15.6, 15.5, 15.9, 15.1, 16, 19.4, >21.5, 23.7, 18.7, 23.8, 18, 16.2, 18.5, 20.6, 18.3, 22.5, 26.9, >19.4, 15.9, 20.5), oktober = c(21.4, 20.8, 14, 17, 23, 26.4, >19.6, 22.7, 26.9, 14.7, 15.2, 19.8, 26.9, 20.2, 14.3, 14.8, 18.5, >21.7, 21.4, 21.8), november = c(24.7, 26.2, 29, 21.6, 17.1, 16.9, >19.1, 24.7, 25.4, 19.8, 18.2, 16.3, 17, 17.7, 15.5, 14.7, 15.8, >19.9, 20.4, 23.3), december = c(19.8, 27, 21, 33, 22.6, 28.3, >21.1, 19, 17.3, 27, 30.2, 24.8, 17.9, 17.9, 20.7, 30.9, 36.2, >21, 20.2, 21.3), norm = c("45.8713463281901", "24.047250681782984", >"3.7533684144746324", "38.594241119279324", "26.391897460120358", >"61.746470001194638", "6.8321020448487992", "11.933109250115226", >"51.951891096493924", "37.424611852237945", "5.1587836676942374", >"36.552835044409434", "31.781209673851027", "29.09146215582853", >"4.856812959269508", "5.3982910143166514", "46.553976273304215", >"17.566272518985429", "20.552451905814117", "61.894775704479279" >)), .Names = c("januari", "februari", "maart", "april", "mei", >"juni", "juli", "augustus", "september", "oktober", "november", >"december", "norm"), row.names = c(NA, 20L), class = "data.frame") > >I transform my dataset with the following script: > >y <- melt(dataset,na.rm=TRUE) >variable <- y[,1] >value <- y[,2] > >and can then perform a levene test as follows: > >LEVENE <- leveneTest(value~variable,y) > >When the dataset is small, lets say less than 100 values per column >everything works great. I get the message: > >No id variables; using all as measure variables > >When the dataset is much bigger I get the following message > >Using norm as id variables, why does this function pick norm as id >variable? and how can I tell R that each column title is my variable > > >Met vriendelijke groeten - With kind regards, > >Joachim Audenaert >onderzoeker gewasbescherming - crop protection researcher > >PCS | proefcentrum voor sierteelt - ornamental plant research > > >Schaessestraat 18, 9070 Destelbergen, Belgi� >T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95 >E: joachim.audena...@pcsierteelt.be | W: www.pcsierteelt.be > > > >From: PIKAL Petr <petr.pi...@precheza.cz> >To: Joachim Audenaert <joachim.audena...@pcsierteelt.be>, " >r-help@r-project.org" <r-help@r-project.org> >Date: 16/04/2015 12:13 >Subject: RE: [R] melt function chooses wrong id variable with >large datasets > > > > >Hi > >There is something weird with your data and melt function. > >AFAIK melt does not use first row as id.variables. > >What is result of > >str(dataset) > >Instead of > >melt(dataset,id.vars=dataset[1,], na.rm=TRUE) > >melt expects something like > >melt(dataset, id.vars=c("norm, "jaar"), na.rm=TRUE) > >If you want more specific answer you shall show us part of your data, >preferably copy output of > >dput(dataset[1:20,]) > >into your mail. > >Cheers >Petr > >> -----Original Message----- >> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of >Joachim >> Audenaert >> Sent: Thursday, April 16, 2015 11:37 AM >> To: r-help@r-project.org >> Subject: [R] melt function chooses wrong id variable with large >> datasets >> >> Hello all, >> >> I'm using a large dataset consisting of 2 groups of data, 2 columns >in >> excel with a header (group name) and 15 000 rows of data. I would >like >> like to compare this data, so I transform my dataset with the melt >> function to get 1 column of data and 1 column of ID variables, then I >> can apply different statistical tests. With small datasets this works >> great, the melt function automatically chooses the name in row 1 as >ID >> variable and melts the data, thus giving me a matrix with all ID >> variables in column one and the data accordingly in column 2. >> With this big dataset however it chooses the whole first column as ID >> variables in stead of the first row. Is there a reason why this >happens >> and how can I make sure the first row is chosen as ID variabele and >the >> lower rows as data? >> >> If I specify that I want the first row to be the id variable I also >get >> error. >> >> melt(dataset,id.vars=dataset[1,], na.rm=TRUE) >> >> Error: id variables not found in data: norm, jaar >> >> Are there alternative ways to create a good reshaped dataset? >> >> Met vriendelijke groeten - With kind regards, >> >> Joachim Audenaert >> onderzoeker gewasbescherming - crop protection researcher >> >> PCS | proefcentrum voor sierteelt - ornamental plant research >> >> Schaessestraat 18, 9070 Destelbergen, Belgi >> T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95 >> E: joachim.audena...@pcsierteelt.be | W: www.pcsierteelt.be >> >> Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? | >> Het PCS op LinkedIn Disclaimer | Please consider the environment >before >> printing. 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Think >green, >keep it on the screen! > [[alternative HTML version deleted]] > > > >------------------------------------------------------------------------ > >______________________________________________ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.