Hi Hermann,
This isn't much more elegant, but
test.list<-sapply(test,function(x) { strsplit(x," ") },simplify=TRUE)
names(test.list)<-NULL
Jim
On 4/15/15, Hermann Norpois <hnorp...@gmail.com> wrote:
> Hello,
>
> I try to open a text file test.txt with the content
>
> * a b d
> * z u i h hh
> * h bh kk
>
> so that I get a list with each line as a vector with the letters as
> elements of the the vector.
>
> My approach ...
> test <- scan ("test.txt", what="character", sep="\n")
> Read 3 items
>> test.list <- lapply (test, function (x) {a <- unlist (strsplit(x," ")); a
> <- a[-1]})
>> test.list
> [[1]]
> [1] "a" "b" "d"
>
> [[2]]
> [1] "z" "u" "i" "h" "hh"
>
> [[3]]
> [1] "h" "bh" "kk"
>
> ... the result is okay but I dont think it is an elegant solution. One
> comment: I dont know how many lines my "real" test.txt will have.
> Thanks Hermann
>
> [[alternative HTML version deleted]]
>
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