Hi, Please don't put quotes around your code. It makes it hard to copy and paste. Alternatively, don't post in HTML, because it screws up your code.
On Wed, Apr 8, 2015 at 8:57 PM, samarvir singh <samarvir1...@gmail.com> wrote: > So I have a list that contains certain characters as shown below > > `list <- c("MY","GM+" ,"TY","RS","LG")` That's a character vector, not a list. A list is a specific type of object in R. > And I have a variable named "CODE" in the data frame as follows > > `code <- c("MY GM+", ,"LGTY", "RS","TY")` That doesn't work, and I have no idea what you expect to have there, so I'm deleting the extra comma. Also, your vector is named code, not CODE. code <- c("MY GM+", "LGTY", "RS","TY") x <- c(1:4) > 'x <- c(1:5) > `df <- data.frame(x,code)` You problably actually want mydf <- data.frame(x, code, stringsAsFactors=FALSE) Note I changed the name, because df() is a base R function. > Now I want to create 5 new variables named "MY","GM+","TY","RS","LG" > > Which takes binary value, 1 if there's a match case in the CODE variable > > df > x code MY GM+ TY RS LG > 1 MY GM+ 1 1 0 0 0 > 2 0 0 0 0 0 > 3 LGTY 0 0 1 0 1 > 4 RS 0 0 0 1 0 > 5 TY 0 0 1 0 0 grepl() will give you a logical match data.frame(mydf, sapply(code, function(x)grepl(x, mydf$code)), stringsAsFactors=FALSE, check.names=FALSE) Sarah -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.