Le 27 mars 2015 � 18:01, David Winsemius <dwinsem...@comcast.net> a �crit :
>
> On Mar 27, 2015, at 3:41 AM, St�phane Adamowicz wrote:
>
>> Well, it seems to work with me.
>>
>
> No one is doubting that it worked for you in this instance. What Peter D. was
> criticizing was the construction :
>
> complete.cases(t(Y))==T
>
> ... and it was on two bases that it is "wrong". The first is that `T` is not
> guaranteed to be TRUE. The second is that the test ==T (or similarly ==TRUE)
> is completely unnecessary because `complete.cases` returns a logical vector
> and so that expression is a waste of time.
>
Indeed, You are right, the following code was enough :
� Z <- Y[, complete.cases(t(Y) ] �
However, in order to help me understand, would you be so kind as to give me a
matrix or data.frame example where � complete.cases(X)== T � or �
complete.cases(X)== TRUE � would give some unwanted result ?
St�phane
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