Hello, Alaios,
try
is.null( Mylist[[i]]$parameters)
It returns TRUE if your list doesn't have a component named "parameters"
or if that component contains NULL.
HtH -- Gerrit
On Tue, 3 Mar 2015, Alaios via R-help wrote:
Hi all,I have a list that has the following fields.
$`80`
[1] "Error in if (fitcass1[[2]] == \"Error\") { : \n Fehlender Wert, wo TRUE/FALSE
nötig ist\n"
attr(,"class")
[1] "try-error"
attr(,"condition")
<simpleError in if (fitcass1[[2]] == "Error") { print(sprintf("error at fitting
gamma distribution with %s periods. Mean %f %f Sd %f %f", flag, mean1, mean2, sd1, sd2))}
else { return(fitcass1)}: Fehlender Wert, wo TRUE/FALSE nötig ist>
$`81`
[1] 0
$`9`
[1] 0
$`79`
$parameters
pi mu sigma
1 0.9996796725 1.654832 127.6542
2 0.0003203275 17183.001125 302.8063
$se
pi.se mu.se sigma.se
1 2.113882e-05 0.1439152 14.22274
2 2.113882e-05 38.3582148 NaN
$distribution
[1] "gamma"
and so one. The content of each first level sublist are never the same. I want
for each first-level sublist my list has to check fast that the current element
, lets say the 79th has the $parameters.then I would keep only the numbers from
the sublists that have this $parameters inside them and skip all the rest.
I tried something like exists(Mylist[[i]]$parameters) but it does not workI
also tried the is.numeric(Mylist[[i]]$parameters)) but this line fails when the
current sublist does not contain the $parameters field.
Can you please help me sort this out?
RegardsAlex
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and provide commented, minimal, self-contained, reproducible code.
