You cannot do that in one step. Do it right after:
names(out) <- df$nm
Please don't post using HTML format.. it scrambles code, and since we cannot
see what you saw it doesn't help in any way.
Also note that "df" is a function in the base stats package... not a good name
to use.
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Sent from my phone. Please excuse my brevity.
On February 20, 2015 7:44:41 AM PST, Alexander Shenkin <ashen...@ufl.edu> wrote:
>Hello all,
>
>I've been trying to figure out how to return a named list from foreach.
>
>Given that the order of the returned list is guaranteed to be in the
>order in which the object is passed to foreach, list members can be
>named afterwards. However, I'm wondering if there's a better way to do
>
>it, perhaps with some sort of combine function?
>
> library(doParallel)
> library(foreach)
>
> cl <- makeCluster(4)
> registerDoParallel(cl)
>
> df = data.frame(nm = letters[11:20], a = 1:10, b=11:20)
>
> out = foreach(i=1:nrow(df)) %dopar% {
> a = list(j = sqrt(df[i,]$a), k = sqrt(df[i,]$b))
> a
> }
>
>How do I name the elements of "out" using the corresponding values
>df$nm?
>
>thanks,
>allie
>
> [[alternative HTML version deleted]]
>
>______________________________________________
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>and provide commented, minimal, self-contained, reproducible code.
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