Great! Thanks, Aravind.
On Monday, February 16, 2015 10:50 PM, Aravind Jayaraman
<aravindjayaramana...@gmail.com> wrote:
Hi,
I think you need not split the data.frame to get the desired result.
You can work with your list lst4 itself.
#Convert the vectors in the list to data.frames.
lst4 <- lapply(lst4, function(x) {as.data.frame(t(iris1.csv))})
#Get the data.frames in the list to the global environment
list2env(lst4 ,.GlobalEnv)
Regards
On 17 February 2015 at 09:23, Zilefac Elvis via R-help
<r-help@r-project.org> wrote:
> Hi All,I have a dataframe called 'means' as shown below:iris1.csv <- iris
> iris2.csv <- iris
> names <- c("iris1.csv", "iris2.csv")
> dat <- mget(names)
> lst4 <- lapply(dat, function(x) apply(x[,-5], 2, mean))
>
> # Build the new data frame
> means <- as.data.frame(do.call(rbind, lst4))
> means$source <- names(lst4)
> means
> # Sepal.Length Sepal.Width Petal.Length Petal.Width isv
> source
> # iris1.csv 5.843333 3.057333 3.758 1.199333 0.3333333
> iris1.csv
> # iris2.csv 5.843333 3.057333 3.758 1.199333 0.3333333
> iris2.csvQUESTION: How can I split 'means' such that there are two files
> (dataframes) on my workspace:datframe 1# Sepal.Length Sepal.Width
> Petal.Length Petal.Width isv
> # iris1.csv 5.843333 3.057333 3.758 1.199333
> 0.3333333dataframe 2:# Sepal.Length Sepal.Width Petal.Length
> Petal.Width isv# iris2.csv 5.843333 3.057333 3.758
> 1.199333 0.3333333
> Many thanks,Asong.
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
J.Aravind
Scientist
Germplasm Conservation Division
ICAR-National Bureau of Plant Genetic Resources
New Delhi - 110 012
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